Answer:
a. 215.6 in^3
b. 1.51 lb
Step-by-step explanation:
The area of each hand grip hole is that of a circle of radius 0.6 in together with a rectangle 2 in long and 1.2 in wide. So, that area is ...
π·(0.6 in)^2 + (2 in)(1.2 in) = (0.36π +2.4) in^2
The area of the kickboard before the hand grip holes are put in is that of a semicircle of radius 5.5 in together with a rectangle 12 in long and 11 in wide. So, that area is ...
(1/2)·π·(5.5 in)^2 + (12 in)(11 in) = (15.125π +132) in^2
Taking the hand grip holes out, the top area of the board is ...
((15.125π +132) -2(0.36π +2.4)) in^2
= (14.405π + 127.2) in^2
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a. The volume is the product of the area and the thickness, so is ...
((14.405π +127.2) in^2)·(1.25 in) ≈ 215.568 in^3
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b. The weight of the kickboard is the product of its volume and its density:
(215.568 in^3)(0.007 lb/in^3) ≈ 1.509 lb
Answer:
Step-by-step explanation:
To find the vertex, change the following equation into graphing form (vertex form)
(x-3)^2-4 - graphing form
The vertex is (3,-4) because you find the x intercept by doing the opposite of -3, and -4 is in the equation.
vertex=
(3,-4)
Answer:
y = 3/11(x) - 19/11
Step-by-step explanation:
Step 1: Subtract 3x from both sides.
Step 2: Divide both sides by -11.
Therefore, the answer is y = 3/11(x) - 19/11.
What do you need help with ASAP?
Answer:
81/4
Step-by-step explanation:
I know this because I did this before
