Question

In a bag of sweets, 6 are orange and 9 are lime. Jodi chooses a sweet at random, eats it an

Answer 1

Answer:$\frac{17}{35}$

Step-by-step explanation:

Given

The bag contains 6 orange and 9 lime sweets

For both sweets of the same flavor, Jodi must either choose orange or lime

No. of ways it can be done is $^6C_1\times^5C_1+^9C_1\times^8C_1$

The total no of ways of selecting two sweets out of 15 is $^{15}C_1\times^{14}C_1$

The probability that both sweets are the same flavor

$P=\dfrac{^6C_1\times^5C_1+^9C_1\times^8C_1}{^{15}C_1\times^{14}C_1}=\frac{102}{210}=\frac{51}{105}=\frac{17}{35}$