Round 37.74 to the ones place.
2 answers:
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Answer:
37.27% probability that he or she will have a heart attack.
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Periodontal disease
Event B: Heart attack
Researchers discovered that 82% of people who have suffered a heart attack had periodontal disease, an inflammation of the gums.
This means that
Only 33% of healthy people have this disease.
This means that
Suppose that in a certain community heart attacks are quite rare, occurring with only 15% probability.
This means that
If someone has periodontal disease, what is the probability that he or she will have a heart attack
37.27% probability that he or she will have a heart attack.
Answer:
(0.767,0.833)
Step-by-step explanation:
The 95% confidence interval for population proportion p can be computed as
The z-value associated with 95% confidence level is 1.96.
whereas p=x/n
We are given that x=440 and n=550.
p=440/550=0.8
Thus, the required confidence interval is
0.767<P<0.833 (rounded to 3 decimal places)
Hence, we are 95% confident that our true population proportion will lie in the interval (0.767,0.833)