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Alex_Xolod [135]
3 years ago
5

I am trying to test out the software Classroom relay and I am just ask if there is any way kids can stop Classroom relay form se

eing their screen and tabs ?
Computers and Technology
2 answers:
Ratling [72]3 years ago
8 0

Answer:

just don't share your screen in the class or if your a teacher just call them out

Explanation:

mote1985 [20]3 years ago
3 0
No they can’t stop it
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Select all that apply.
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Thank You!
8 0
4 years ago
Create an ArrayList of strings to store the names of celebrities and athletes. Add 5 names to the list. Process the list with a
mr Goodwill [35]

Answer:

// ArrayList class is imported

import java.util.ArrayList;

// Iterator class is imported

import java.util.Iterator;

// Main class is defined

class Main {

   // main method to begin program execution

   public static void main(String args[]) {

       // names ArrayList of String is defined

       ArrayList<String> names = new ArrayList<>();

       // 5 names are added to the list

       names.add("John");

       names.add("Jonny");

       names.add("James");

       names.add("Joe");

       names.add("Jolly");

       // for loop to print the names inside the arraylist

       for(int index = 0; index <names.size(); index++){

         System.out.println(names.get(index));

       }

       

       // A blank line is printed

       System.out.println();

       // A newMethod is called with names as argument

       newMethod(names);

       // A blank line is printed

       System.out.println();

       // Instance of Iterator class is created on names

       Iterator<String> iter

           = names.iterator();

 

       // Displaying the names after iterating

       // through the list

       while (iter.hasNext()) {

           System.out.println(iter.next());

       }

   }

   // the newmethod is created here

   public static void newMethod(ArrayList<String> inputArray){

     // A new name is added at index 2

     inputArray.add(2, "Smith");

     // the name in index 4 is removed

     inputArray.remove(4);

     // for each is used to loop the list and print

     for (String name : inputArray) {

       System.out.println(name);

       }

   }

}

Explanation:

The code is well commented. An output image is attached.

7 0
4 years ago
Just answer the 2 questions. THX
pogonyaev

Answer:

A then D

Explanation:

3 0
3 years ago
1. INTRODUCTION In this project, you will gain experience with many of the Python elements you’ve learned so far, including func
yulyashka [42]

Answer:

See Explaination

Explanation:

def process_string(s):

global char#global varibles

char=[]

global count

count=[]

for i in s:

#checking whether i is alphabet or not

if(i.isalpha()):

#converting to lower

i=i.lower()

if i in char:

#if char already present increment count

count[char.index(i)]+=1

else:

#if char not present append it to list

char.append(i)

count.append(1)

#menu

print("1. Enter a string")

print("2. Display the string")

print("3. Reverse the string")

print("4. Append a string to the existing one")

print("5. Slice the string")

print("6. Display the number of occurences of each letter")

print("7. Quit")

op=input("Enter option:")

#as I don't know what you have covered

#I am trying to make it simple

#checking whether input is numeric or not

#you can use try except if you want

while(not op.isnumeric()):

op=input("Enter valid option:")

op=int(op)

global x

while(op!=7):

if(op==1):

x=input("Enter a string: ")

elif(op==2):

print("The string is:",x)

elif(op==3):

x=x[::-1]#reversing the string

print("The string is:",x)

elif(op==4):

y=input("Enter a string: ")

x=x+y #string concatnation

elif(op==5):

a=input("Enter first integer: ")

while(not a.isnumeric()):

a=input("Enter valid first integer: ")

a=int(a)

b=input("Enter second integer: ")

while(not b.isnumeric()):

b=input("Enter valid second integer: ")

b=int(b)

x=x[a:b]#string slicing

#you can also use x.slice(a,b)

elif(op==6):

process_string(x)

for i in range(len(char)):

print(char[i],",",count[i])

else:

#incase of invalid input

print("Invalid option")

print("1. Enter a string")

print("2. Display the string")

print("3. Reverse the string")

print("4. Append a string to the existing one")

print("5. Slice the string")

print("6. Display the number of occurences of each letter")

print("7. Quit")

op=input("Enter option:")

while(not op.isnumeric()):

op=input("Enter valid option:")

op=int(op)

6 0
3 years ago
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