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Pepsi [2]
3 years ago
9

Find the area of a parallelogram with these dimensions.

Mathematics
1 answer:
aev [14]3 years ago
3 0
The area is 14! hope this helps
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Whats 9+10??????????
nikdorinn [45]
The answer to 9+10 is 19 because if you add 9 to the number 10, you get 19
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Popular magazines rank colleges and universities on their ""academic quality"" in serving undergraduate students. Describe two c
Reika [66]

Answer:

Quantitative: i) The number of students in the school vis - a - vis the number of classes in the school. In order words, simply number of students per class

ii) The rate of graduation of students.

Categorical:i) Courses being taken by students

ii) Region of country of students.

Step-by-step explanation:

To answer this question effectively, it's important for us to know that a quantitative variable usually has numerical values, and also have units of measure as well while categorical variables simply places each student into a specific category.

Now, the two quantitative variables we will consider are;

i) The number of students in the school vis - a - vis the number of classes in the school. In order words, number of students per class

ii) The rate of graduation of students.

Also, the two categorical variables we will consider are;

i) Courses being taken by students

ii) Region of country of students

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3 years ago
The quotient of m2 – 9 divided by m-3 is<br> a) m-3 b) m+3 c) m
DaniilM [7]

Answer:m+3

Step-by-step explanation:

4 0
3 years ago
5pts and the person who has the correct answer gets brainliest​
Tanzania [10]

Answer:

4

Step-by-step explanation:

The one that weighs the less is 80

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6 0
2 years ago
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Please help please these are short answers
atroni [7]

Answer: The answers are given below.


Step-by-step explanation:  The calculations are as follows:

(19) Weight of the puppy last week is

W_\ell=2\dfrac{1}{2}~\textup{lb},

and weight of the puppy this week is

W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.

Therefore, the weight gained by the puppy is given by

W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

H_\ell=\dfrac{4}{9}~\textup{hr},

and the time taken by Nazia to complete her Mathematics homework is

H_m=\dfrac{2}{9}~\textup{hr}.

Therefore, Nazia takes more time to complete Language Arts homework, by

H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.

(22) Quantity of Aluminium collected by Maya is

A_m=\dfrac{4}{20}=0.2~\textup{lb},

and the quantity of Aluminium collected by her friend Abigail is

A_a=\dfrac{7}{8}=0.87~\textup{lb}.

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.

(23) Quantity of snow fall last Wednesday is

S_w=3\dfrac{1}{4}=3.25~\textup{in.},

and quantity of snowfall on sunday is

S_s=3\dfrac{4}{5}=3.8~\textup{in.}.

Therefore, quantity of snowfall was more on Sunday by

S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.

Thus, all the questions are answered.

3 0
3 years ago
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