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2 years ago

WILL GIVE BRAINLIEST

Mathematics

2 answers:

bearhunter [10]2 years ago

8 0

Answer:

the best way to write is as it is in the beginning, so 1.2×10^-6, that is the alternative A.

LekaFEV [45]2 years ago

4 0

Answer:

b good luck srro if u am rong

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PLEASE, I NEED HELP! I will not accept nonsense answers, but I will give the person a BRAINLIEST if you get it correct.

alex41 [277]

Answer: The last choice is correct. Edna can score 5 times as many points in the next level as in the level she has reached

Step-by-step explanation: chart of values for $y= 5^{x}$

x is the level y, points possible)

x y

1 5

2 25

3 125

4 625

5 3125

You can see the exponential pattern

For what it's worth, two views of the graph of the equation are attached

The point values are astronomical!

6 0

3 years ago

you got a new credit card with an interest rate of 18% compounded monthly and no minimum payment. you go on a shopping spree and

just olya [345]

The total amount owed after 6 months will be found using the formula:
FV=P(1+r/100*n)^n
P=principle=$10000
r=rate=18%
n=terms=0.5

FV=10000(1+18/2*100)^0.5
FV=$10,440.30651
Thus the amount owed will be $10440.30651

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

7 0

2 years ago

Please help! will give brainliest !!

Veseljchak [2.6K]

Answer:

1, 2, 8, 128, 32768

Step-by-step explanation:

$recursive \: formula: \\ a _{n} = 2. {( a_{n - 1} )}^{2} \\ \\ a _{1} = 1...(given) \\ \\ a _{2} = 2. {( a_{2 - 1} )}^{2} = 2 {(a _{1} )}^{2} = 2 {(1)}^{2} \\ \\ a _{2} = 2\\ \\a _{3} = 2. {( a_{3 - 1} )}^{2} = 2 {(a _{2} )}^{2} = 2 {(2)}^{2} \\ \\ a _{3} = 8\\ \\a _{4} = 2. {( a_{4 - 1} )}^{2} = 2 {(a _{3} )}^{2} = 2 {(8)}^{2} \\ \\ a _{4} = 128\\ \\a _{5} = 2. {( a_{5 - 1} )}^{2} = 2 {(a _{4} )}^{2} = 2 {(128)}^{2} \\ \\ a _{5} = 32,768\\ \\$

Thus the first five terms are: 1, 2, 8, 128, 32768.

5 0

2 years ago

I need help on this question

Harlamova29_29 [7]

Answer: Capitalism

Step-by-step explanation:

hope it helps

6 0

2 years ago