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3 years ago

The line with equation y + 2x = 0 coincides with the terminal side of an angle θ in standard position in Quadrant IV .

Mathematics

1 answer:

Ket [755]3 years ago

7 0

Answer:

-2

Step-by-step explanation:

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Joshua went to the hardware store and bought 4 yellow ropes. The total

shusha [124]

Answer:

15.55m

Step-by-step explanation:

62.2

= 15.55m

Therefore, each rope is 15.55m

5 0

3 years ago

Felicia is a girl who plays on a co-ed volleyball team. Besides Felicia, the team is made up of 7 boys and 4 other girls. The te

lozanna [386]

Answer: IT IS 1/12

Step-by-step explanation:

Because Felica is one of the girls that play and there is 7 boys and 4 others girls, its like saying we need to add 7 + 4 + 1 which is 12 the answer.

If i get this wrong, my apologies are to you, but I'm pretty sure my equation was correct

Thank me later

7 0

3 years ago

In the diagram below, P is circumscribed about quadrilateral ABCD. What is the value of x?

alexira [117]

We know that
In any quadrilateral where the vertices are on the circumference of a circle, the opposite angles add up to $180$ degrees.

So,
in this problem
$(x+20) + 110 = 180 \\ x+130=180 \\ x=180-130 \\ x=50degrees$

therefore

the answer is
$x=50degrees$

7 0

3 years ago

Read 2 more answers

What is the slope intercept form of 5x-y=9

Korolek [52]

Slope-intercept:
y=mx+b

5x-y=9
5x=y+9
y+9=5x
y=5x-9

Slope-int: y=5x-9

7 0

3 years ago

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Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

6 0

3 years ago

Read 2 more answers