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fomenos
3 years ago
11

1. What is the value of x in the figure? (4x + 2) 150°

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0
X = 37
150= 4x + 2
148 = 4x
X = 37
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Solve quadratic inequality x^2+4x≥0
klemol [59]

Answer:

Step-by-step explanation:

y = x² + 4x is an up-opening parabola with x-intercepts 0 and -4.

y ≥ 0 when x≤-4 or x≥0

range: (-∞,-4)∪[0,+∞)

7 0
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<img src="https://tex.z-dn.net/?f=f%20%2B%20523.89%20%20%3D%20812.57" id="TexFormula1" title="f + 523.89 = 812.57" alt="f + 523
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8 0
3 years ago
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34
Vadim26 [7]

Answer:

They are similar by the definition of similarity in terms of a dilation

Step-by-step explanation:

The given vertices of triangle ΔABC are;

A(1, 5), B(3, 9), and C(5, 3)

The vertices of triangle ΔDEF are;

D(-3, 3), E(-2, 5), and F(-1, 2)

Therefore, we get;

The length of segment, \overline{AB} = √((9 - 5)² + (3 - 1)²) = 2·√5

The length of segment, \overline{BC} = √((9 - 3)² + (3 - 5)²) = 2·√10

The length of segment, \overline{AC} = √((5 - 3)² + (1 - 5)²) = 2·√5

The length of segment, \overline{DE} = √((5 - 3)² + (-2 - (-3))²) = √5

The length of segment, \overline{EF} = √((2 - 5)² + (-1 - (-2))²) = √10

The length of segment, \overline{DF} = √((2 - 3)² + (-1 - (-3))²) = √5

∴ \overline{AB}/\overline{DE} = 2·√5/(√5) = 2

\overline{BC}/\overline{EF} = 2·√10/(√10) = 2

\overline{AC}/\overline{DF} = 2·√5/(√5) = 2

The ratio of their corresponding sides are equal and therefore;

ΔABC and ΔDEF are similar by the definition of similarity in terms of dilation.

4 0
3 years ago
What is 4 + x / 7=2​
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Answer:

-14

Step-by-step explanation:

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