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Reika [66]
3 years ago
15

Find the ratio of lengths 3 meters to 6 cm

Mathematics
1 answer:
jeka57 [31]3 years ago
6 0

Step-by-step explanation:

Convert metre to centimetre

Recall: 1m = 100cm

That means,

3m = 3 * 100cm = 300cm

Now we compare them since they have the same unit.

300cm : 6cm

50 : 1

Answer = 50 : 1

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A rocket launches from rest and reaches a velocity on 12,000 m/s in 8 seconds. What is the acceleration? *
Snezhnost [94]

Answer:

Step-by-step explanation:

The rocket accelerates by burning the fuel it carries and ejecting the burned ... As a result, it permitted multiple launches as opposed to single-use rockets. ... we can use Newton's second law to calculate the consequent acceleration. ... (a) A 5.00-kg squid initially at rest ejects 0.250 kg of fluid with a velocity of 10.0 m/s.

7 0
2 years ago
Is this solved correctly ?
nadezda [96]
Yes i believe so snnsndneneneme sna
7 0
3 years ago
Two angles are complements if their sum is 90 degrees. The measure of one angle is one third the measure of its complement. Find
zysi [14]

Answer:

22.5 degrees

Step-by-step explanation:

90 = x + 3x

90 = 4x (divide by 4)

22.5 = x

22.5 + 67.5 = 90

5 0
3 years ago
The numbers below show a pattern 0.006 0.6 6
Ivenika [448]

Answer:

Yes

Step-by-step explanation:

The decimal points moves to the right at a constant pace.

0.006 -> 0.06 -> 0.6 -> 6

In other words, we are just multiplying each one by 10 to get the next value.

Best of Luck!

7 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
2 years ago
Read 2 more answers
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