Answer:
b= 10 miles/hr and c= 5 miles/hr
Step-by-step explanation:
Let it's downstream and upstream speed be d and u respectively
also speed of the boat be b and speed of stream be c.
as per question d = 150/10= 15 miles/hr
and, u= 150/30= 5 miles/hr
also we know d= b+c = 15.....i and u = b-c= 5....ii
solving i and ii we get b= 10 miles/hr and c= 5 miles/hr
Answer:
Step-by-step explanation:
When Riko left his house, Yuto was 5.25 miles along the path.
Average speed of Riko = 0.35 miles per minute
Average speed of Yuto = 0.25 miles per minute
First we will calculate the time in which Riko will catch Yuto on the track.
Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto
= 0.35 - 0.25
= 0.10 miles per minute
Now we this relative velocity tells that Riko is moving and Yuto is in static position.
By the formula,
Average speed = 
0.10 = 
t = 
t = 52.5 minutes
Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.
So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5
Here time can not be less than zero because time can not be with negative notation. It will always start from 0.
Answer:
(-1,10)
Step-by-step explanation:
At the point when the paths cross, the respective x and y values of each equation will be equal.
Your path is y=2x+12, and your friends path is 4x+y=6. Sub 2x+12 in for y (from your path's equation) into your friends equation to find the value of x:
4x+2x+12=6
6x=-6
x=-1
y=2x+12
y=2(-1)+12=10
So you will cross paths at (-1,10)