Nerve impulses are picked up by a neuron’s:

How many moles are there in 6.33x10^23 molecules of NH3?

nadezda [96]

About 1.051 moles (depends on how u round it)

6 0

3 years ago

A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.

Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

$[SCN^-]=0.00012 mol/L$

The analytical concentrations of ferric ions:

$[Fe^{3+}]=0.063 mol/L$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

1) Moles of sodium thiocyanate = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = $4.8\times 10^{-4} M$

$n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol$

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in $2.4\times 10^{-6}mol$ of NaSCN.

$=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol$

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

$n'=0.002 M\times 0.21 L=0.00042 mol$

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

$3\times 0.00042 mol=0.00126 mol$

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

$[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L$

The analytical concentrations of ferric ions:

$[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L$

3 0

3 years ago

Read 2 more answers

How to find efficiency of a pulley system

Digiron [165]

Multiply the weight of the object by the distance it traveled to find the amount of work output. For the example: 10 lbs. x 1 foot = 10 foot-pounds. Find the work efficiency by dividing the work output by the work input and multiplying by 100.

8 0

4 years ago

50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0

creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA = 0.010 × 50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0

3 years ago

Describe how the properties of the compound carbon monoxide (CO) differ from the properties of the

ElenaW [278]

Explanation:

There is a clear cut difference between a compound and an element:

A compound is made up of substances composed of two or more kinds of atoms or elements joined together in a definite grouping.
An element is a distinct substance that cannot be split-up into simpler substances. These substances are only made up of one kind of atom.

Compounds are formed so that unstable elements can attain stability.

Carbon monoxide is made up two elements: Carbon and oxygen that have combined chemically together.

Carbon monoxide is a toxic gas and it is different from oxygen atom and carbon atom.
Carbon is a solid but carbon monoxide is a gas.
Oxygen atom does not exists on its own but it exists as Oxygen gas O₂
The properties of carbon monoxide clearly differ from that of oxygen and carbon.

Learn more:

Elements brainly.com/question/1781595

#learnwithBrainly

7 0

3 years ago