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DanielleElmas [232]
4 years ago
13

Why did one liter of nitrogen prepared by lord rayleigh appear to have a greater mass than the other liter prepared by a differe

nt method?
Chemistry
1 answer:
Snowcat [4.5K]4 years ago
8 0
There were two methods that Lord Rayleigh used in his experiment. First, nitrogen was obtained from the atmosphere by passing air over hot copper. Second, air was bubbled through an ammonia mixture, then passed over hot copper. The second method would have a greater mass of nitrogen than the first, <em>because the nitrogen from the atmosphere was contaminated by the nitrogen from the ammonia mixture.</em>
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Formula for the compound Tetraoxygen nonabromide?
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O4Br9

Explanation:

Tetra means 4 and nona means 9. Just use these prefixes to decide how many of each element you have.

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How were the elements in the first periodic table arranged?
Snezhnost [94]

Based on atomic mass

Explanation:

Elements were arranged on the first periodic table based on their atomic masses.

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Periodic table brainly.com/question/2690837

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5 0
4 years ago
What characteristics of a metallic bond explains some of the properties of metals
d1i1m1o1n [39]

Answer:

See Explanation

Explanation:

Metallic bonds involve attraction between electrons and positively charged metal ions. The metals are ionized and electrons form a sea of valence electrons. These loosely bound electrons surround the nuclei of the metals.

The presence of this sea of electrons explains the fact that metals conduct electricity and heat due to the free valence electrons.

Due to the nature of the bonding between metal atoms,metals are malleable and ductile.

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8 0
3 years ago
A balloon is inflated with helium to a volume of 45L at room temperature (298K). If the balloon is cooled to 200.K, what is the
igor_vitrenko [27]

Answer:

V₂ = 30.20 L

Explanation:

Given data:

Initial volume = 45 L

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Final temperature = 200 K

Final volume = ?

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The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

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T₁ = Initial temperature

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T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 45 L × 200 K / 298 k

V₂ = 9000 L.K / 298 K

V₂ = 30.20 L

8 0
3 years ago
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