Answer:
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We have that the original pressure of this gas is mathematically given as
P2=17.854 kPa
<h3>
Boyle's law</h3>
Question Parameters:
AT constant temperature, a gas is compressed from 5.5 L to 1 L.
At 1 L, the pressure of the gas is 98.2 kPa
Generally the equation for Boyle's law is mathematically given as
P1V1=P2V2
Therefore

P2=17.854 kPa
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Answer:
Explanation:
Phosphoric acid H₃PO₄ is produced from reaction of water and tetraphosphorus decoxide P₄O₁₀ as follows
P₄O₁₀ + 6 H₂O = 4 H₃PO₄
In this reaction 6 molecules of H₂O and one molecule of phosphorus compound P₄O₁₀ is needed to produce phosphoric acid , ie the conversion factor of water to acid is 6 / 1
This ratio is called mole ratio of water to H₃PO₄.
So the required ratio is 6 : 1 .
6+2=8 quarts of a new solution
0.45*6 - quarts antifreeze in <span>a solution that is 45% antifreeze
0.19*2 - </span>quarts antifreeze in a solution that is 19% antifreeze
x- concentration of a new solution
8x - quarts antifreeze in a new solution
0.45*6 + 0.19*2 = 8x
3.08=8x
x= 0.385 =38.5 %