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3 years ago

10 + 32 -6=any one?

Chemistry

1 answer:

Kryger [21]3 years ago

3 0

Answer:

Your answer will be 36

Explanation:

10+32=42

42-6=36

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The (OH) of a given solution =1.00x10-9M. what is this solution s pOH?

german

Answer:

Explanation:

Given parameters:

Concentration of OH⁻ [OH]= 1 x 10⁻⁹M

Solution:

To find the pOH of a solution can be found using the expression below:

pOH = -log₁₀[OH]

[OH] = concentration of the hydroxyl ions

pOH = -log₁₀(1 x 10⁻⁹) = - x -9 = 9

8 0

3 years ago

Read 2 more answers

given a density of 350 grams/cm3 and a mass of 25 grams. What is the volume using the equation involving density?

Eduardwww [97]

0.07cm³

Explanation:

Given parameters:

Density of the body = 350g/cm³

Mass of the body = 25g

Unknown:

Volume of the body = ?

Solution:

Density is the amount of substance contained in a volume of body. It is expressed as:

Density = $\frac{mass}{volume}$

Since the unknown is volume, we make it the subject of the expression;

Volume = $\frac{mass}{density}$

Volume = $\frac{25}{350}$ = 0.07cm³

learn more:

Density brainly.com/question/2690299

#learnwithBrainly

6 0

4 years ago

Use Table 1: Analysis of Decay in the laboratory guide to answer this question: Scientists find a piece of wood that is thought

Sladkaya [172]

We are given the initial amount of 1 million carbon-14 atoms and the final amount which is 1/16 of the current atmospheric 14C levels. Also, the half life of carbon is 5,750 years. WE can use the decay formula

Aₓ = A₀e^-(ln2/t1/2)t
1,000,000(1/16) = (1,000,000)e^-(ln2/5750)t
t = 23,000 years

6 0

3 years ago

using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius

lukranit [14]

Answer:

Please, see attached two figures:

The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

Answer: 5.5g

Explanation:

The red arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the solubility of NH₄Cl.

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

$10mL\times 1.0g/mL=10g$