The Quadrilateral ABCD with coordinates (3, 1), (4, 4), (7, 5), (6, 2) is a rhombus because its length and width are both square root of 10 units and adjacent sides are not perpendicular. This can be seen by plotting the points you can either plot it or by using programs.
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Answer:
C
Step-by-step explanation:
y(x) = x^(1/3)+7
y(-8)=(-8)^(1/3)+7=5
y(-1)=(-1)^(1/3)+7=6
y(1)=(1)^(1/3)+7=8
y(8)=(8)^(1/3)+7=9
Step-by-step explanation:
$15
He keeps 8. He saves 5 so 8+5=13
He also gives $2 to charity.
8+5+2= $15
Answer:
The interval [32.6 cm, 45.8 cm]
Step-by-step explanation:
According with the <em>68–95–99.7 rule for the Normal distribution:</em> If 
is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval
![\large [\bar x - s, \bar x +s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-%20s%2C%20%5Cbar%20x%20%2Bs%5D)
around 95% of the data must fall in the interval
![\large [\bar x -2s, \bar x +2s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-2s%2C%20%5Cbar%20x%20%2B2s%5D)
around 99.7% of the data must fall in the interval
![\large [\bar x -3s, \bar x +3s]](https://tex.z-dn.net/?f=%5Clarge%20%5B%5Cbar%20x%20-3s%2C%20%5Cbar%20x%20%2B3s%5D)
So, the range of lengths that covers almost all the data (99.7%) is the interval
[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]
<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>
Answer:
add x
Step-by-step explanation:
The operation "subtract 5" has eliminated the constant from the right side of the equation, so the next step would be to eliminate the variable from the left side. You do that by adding the opposite of the variable term.
The opposite of the term -x is x, so we "add x" as the next step.
This makes the solution look like ...
-x +6 = 5 -3x
-x +1 = -3x . . . . . . subtract 5
1 = -2x . . . . . . . . . add x
-1/2 = x . . . . . . . . .divide by -2
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<em>Comment on this solution</em>
My preference is always to add the opposite of the variable term with the smallest coefficient. Here, that term is -3x, so I would add 3x as a first step. This leaves the only x-term with a <em>positive</em> coefficient, so can reduce errors in the solution.
