Answer:
Explanation:
The alkene reactions in general are addition or oxidation reactions. For the addition reaction, we have to take into account that some of them are marknonikov and other anti-markovnikov. Also for the addition reaction, we will have to take into account if we will have anti or syn products. In the oxidation reaction, we have to know the specifics for each reaction. If the reaction can go to the highest oxidation level, is the double bond is broken, etc.
Each reaction has its <u>specific characteristics</u> (see figures 1 and 2).
Answer:
43.2 mol C
115 mol H
158 mol of atoms
Explanation:
Step 1: Given data
Moles of C₃H₈: 14.4 mol
Step 2: Calculate the number of moles of C
The molar ratio of C₃H₈ to C is 1:3. The moles of C are 3/1 × 14.4 mol = 43.2 mol.
Step 3: Calculate the number of moles of H
The molar ratio of C₃H₈ to H is 1:(. The moles of H are 8/1 × 14.4 mol = 115 mol.
Step 4: Calculate the total number of moles of atoms
n = nC + nH = 43.2 mol + 115 mol = 158 mol
Since hydrogen only has 1 electron it shares 1 with flourine to have a pair. It is single bonded.
<span>In this item, we are asked to calculate for the mass of 22.05 mole of octane given that its molecular mass is equal to 114.22 g/mol. To answer this item, we simply have to multiply the number of moles with the molecular mass. That is, (114.22 g/mol)(22.05 mol) which is equal to 2518.221 grams. </span>
