How many moles of sodium hydroxide are contained in 65.0 mL of a 2.20 M solution?
1 answer:
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Answer : The products are Silver sulfide, and Sodium iodide,
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Explanation :
The given balanced chemical reaction is,
From the given balanced reaction, we conclude that the 2 moles of silver iodide react with the 1 mole of sodium sulfide to give product as 1 mole of silver sulfide and 2 moles of sodium iodide.
In a chemical reaction, reactants are represent on the left side of the right-arrow and products are represent on the right side of the right-arrow.
Therefore, in a chemical reaction the products are Silver sulfide and Sodium iodide.
So your answer would pretty much be 2.80 x 10^24. The picture is just the explanation and how you would get that answer.
