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kvv77 [185]
3 years ago
6

Which expression is equivalent to (b^n)^m A.b^n-m B.b^n+m C.b^n×m D.b^n÷m

Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0
b^m*b^n 

= b^m^+^n 

Answer = b
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