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2 years ago

8

In order to play on the 7th-grade basketball team, you must buy a team uniform. Last year a uniform cost $40, but this year a un

iform cost $48. What is the percent of change?
-IMPORTANT-
show work please and thanks

2 answers:

Colt1911 [192]2 years ago

7 0

Answer:

EE

Step-by-step explanation:

baherus [9]2 years ago

5 0

Answer:

1/6 or 16.666%

Step-by-step explanation:

8/48 and there is your answer.

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{y=-x+1<br> {y=4x-14<br> please help me <br> my paper is due today

Temka [501]

$- x + 1 = 4x - 14 \\ - x - 4x = - 14 - 1 \\ - 5x = - 15 \\ x = 3$

Substitute x = 3 in any given equations. I will do in y = - x + 1

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Therefore the answer is (3,-2)

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2 years ago

Joshua scored the same number of points in each of his last 3 basketball games. He

Arte-miy333 [17]

Answer:

24

Step-by-step explanation:

Let x be the points he scored in his best game. x-8 would then represent each of his last 3 games.

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3 years ago

For integers a, b and k, we know that a >12, b > 20 and a < b. If b=7k, what is the value of k ?

Doss [256]

This question is incomplete, the complete question is;

For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?

Answer: the value of k = 2

Step-by-step explanation:

Given that;

a > 12

b < 20

a < b

If b = 7k

Now if k = 1 {b = 7k = 7}

b would be equal to 7 but b has to be greater than 20

IT CANT BE

if k = 2 { b = 7k = 14}

b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,

a has to be less than than b ( 12 < 14 )

IT IS

if k = 3 {b = 7k = 21}

b would be equal to 21, so b is greater than 20 and a is less than 21

IT CANT BE

Therefore the value of k = 2

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3 years ago

Which expression is equal to −2i(4−i)?

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2 years ago

Read 2 more answers

Integrate sin^-1(x) dx<br><br> please explain how to do it aswell ...?

Lynna [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2264253

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}$

Trigonometric substitution:

$\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}$

then,

$\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}$

So the integral $\mathsf{(ii)}$ becomes

$\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}$

Integrate $\mathsf{(ii)}$ by parts:

$\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}$

$\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}$

Substitute back for the variable x, and you get

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus</em>

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2 years ago