Answer:
<u>Momentum of 2 kg ball:</u>
velocity = 6 m/s
momentum (p)= mv
p = (2)(6) kg m/s
p = 12 kg m/s
kg m/s can also be written as 'N'
Force of 2 kg ball = 12 N
<u>Momentum of 3 kg ball:</u>
velocity = 4 m/s
momentum (p) = mv
p = (3)(4)
p = 12 kg m/s
Since kg m/s can also be written as 'N'
Force of 3 kg ball = 12 N
Now that we have the force applied by both the balls, we can find the resultant force using vector addition
2 kg ball's vector = -12 i
3 kg ball's vector = -12 j
Adding both the vectors, we get:
Resultant vector = -12 i -12 j
The speed both the balls will move at, is the magnitude of the resultant vector
Magnitude of the resultant vector:
|R|² = (i vector)² + (j vector)²
|R|² = (-12)² + (-12)²
|R|² = 144 + 144
|R|² = 288
|R| = √288
|R| = 17 m/s (approx)
The balls will move at a velocity of 17 m/s
<u>Direction of the Common velocity:</u>
TanΘ = Opposite / Adjacent
TanΘ = 12 / 12
Tan Θ = 1
Θ = Arctan(1)
Θ = 45 degrees
Therefore, the common velocity will be 45 degrees down from the horizontal
