All categories

3 years ago

What are chemical property for liquid

Physics

1 answer:

Alinara [238K]3 years ago

7 0

surface tension
capillary action
cohesive and adhesive forces
contact angles
viscosity
vapour pressure
wetting agents

You might be interested in

What is agrculture and it means

Zina [86]

<h2>Answer:</h2>

<u><em>Agriculture is the science, the practice of cultivating the soil, art, producing crops, raising livestock, and in varying degrees the preparation and marketing of the resulting products cleared the land to use for agriculture.</em></u>

<h2>Explanation: </h2>

<em>This is what I found during my research and I hope this helps. Correct me if I am incorrect! Have a good one. </em>

5 0

3 years ago

What kind of model is shown below?

Rudiy27

D. a foot model

btw this is a joke right cuz there ain’t no picture lol

7 0

3 years ago

Compare contrast atoms and molecules

creativ13 [48]

Atoms are a single entity (one type of element) whereas a molecule is a group of 2 or more atoms chemically bonded. Don't be confused that atoms are a single particle because they can be split into protons, neutrons and electrons.

5 0

3 years ago

How can oxygen enter the lungs?

Oksanka [162]

I just got this question not to long ago but to answer your question the primary function of the respiratory system is to exchange oxygen<span> and carbon dioxide. Inhaled </span>oxygen enters the lungs<span> and reaches the alveoli. </span>Oxygen<span> passes quickly through this air-blood barrier into the blood in the capillaries. Similarly, carbon dioxide passes from the blood into the alveoli and is then exhaled.</span>

6 0

3 years ago

A string of length L, mass per unit length \mu, and tension T is vibrating at its fundamental frequency. What effect will the fo

viva [34]

The fundamental frequency on a vibrating string is given by:

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where

L is the length of the string

T is the tension

$\mu$ is the mass per unit length of the string

Keeping this equation in mind, we can now answer the various parts of the question:

(a) The fundamental frequency will halve

In this case, the length of the string is doubled:

L' = 2L

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2(2L)}\sqrt{\frac{T}{\mu}}=\frac{1}{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{2}$

So, the fundamental frequency will halve.

(b) the fundamental frequency will decrease by a factor $\sqrt{2}$

In this case, the mass per unit length is doubled:

$\mu'=2\mu$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{T}{2 \mu}}=\frac{1}{\sqrt{2}}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{\sqrt{2}}$

So, the fundamental frequency will decrease by a factor $\sqrt{2}$ .

(c) the fundamental frequency will increase by a factor $\sqrt{2}$

In this case, the tension is doubled:

$T'=2T$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu}}=\sqrt{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\sqrt{2}f$

So, the fundamental frequency will increase by a factor $\sqrt{2}$ .

8 0

3 years ago