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3 years ago

MATHPHYS PLEASE HELP IT SAYS ITS WRONG

Physics

2 answers:

Charra [1.4K]3 years ago

6 0

I can barely see the pic

jarptica [38.1K]3 years ago

3 0

Answer:

0.833 J

Explanation:

The initial kinetic energy of the spike is:

KE = ½ mv²

KE = ½ (0.52 kg) (3.7 m/s)²

KE = 3.56 J

23.4% of this energy is converted to internal energy.

U = 0.234 (3.56 J)

U = 0.833 J

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$\therefore \textrm{Kinetic energy change}= \textrm{Change in potential energy}\\\Rightarrow \dfrac{1}{2}m(v^2-u^2)= \dfrac{kpe}{y}-\dfrac{kpe}{x}\\\Rightarrow \dfrac{1}{2}m(v^2-(0)^2)= \dfrac{kpe}{0.03}-\dfrac{kpe}{0.06}\\\Rightarrow \dfrac{1}{2}mv^2= \dfrac{100kpe}{3}-\dfrac{100kpe}{6}\\\Rightarrow \dfrac{1}{2}mv^2= \dfrac{100kpe}{6}\\$

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Hence, when the electron is at a distance of c cm from the proton, it moves with a velocity of 91.87 m/s.

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