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Sergio [31]
3 years ago
10

MATHPHYS PLEASE HELP IT SAYS ITS WRONG

Physics
2 answers:
Charra [1.4K]3 years ago
6 0
I can barely see the pic
jarptica [38.1K]3 years ago
3 0

Answer:

0.833 J

Explanation:

The initial kinetic energy of the spike is:

KE = ½ mv²

KE = ½ (0.52 kg) (3.7 m/s)²

KE = 3.56 J

23.4% of this energy is converted to internal energy.

U = 0.234 (3.56 J)

U = 0.833 J

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7.
m_a_m_a [10]
I think it’s 5.0 X 10 8Hz
5 0
3 years ago
What happened if there is no frictional force?​
Komok [63]

Answer: Friction stops things from sliding apart. If there was no friction everything would slide to the lowest point. With no friction the only possible movement would be falling to a lower point under gravity.

Explanation: In a frictionless world, more objects would be sliding about, clothes and shoes would be difficult to keep on and it would be very difficult for people or cars to get moving or change direction. Students should be encouraged to consider how dependant their world is on the beneficial action of friction. Humans and other objects will become weightless without gravity. If we have no gravity force, the atmosphere would disappear into space, the moon would collide with the earth, the earth would stop rotating, we would all feel weightless, the earth would collide with the sun, and as a consequence.

4 0
3 years ago
Wave length of sodium light is 5893A express in nanometre​
DaniilM [7]

Answer:

589.3 nm

Explanation:

The wavelength of a sodium light is 5893 A.

We need to find the wavelength in nm.

5893\ A=5893\times 10^{-10}\ m

Also, 1\ nm=10^{-9}\ m

5893\ A=5893\times 10^{-9}\times 10^{-1}\ m\\\\=5893\times 10^{-1}\ nm\\\\=589.3\ nm

So, the wavelength of sodium light is 589.3 nm.

8 0
3 years ago
If there is no slipping, a frictional force must exist between the wheels and the ground. in what direction does the frictional
djyliett [7]
The frictional force is always act in opposite direction of motion. if wheels is moving in +x axis or right then the f force is act in -x or left
8 0
3 years ago
At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m2 . A fan is 30 m from the loudspea
marshall27 [118]

The concepts used to solve this problem are sound power, area of ear drum, and inverse square law.  First find the intensity I_2 using inverse square law for different distances. Then find the area of the ear drum using the diameter and finally find the energy transferred to each ear drum in one second. Intensity is inversely proportional to the square of the distance from the source:

I \propto \frac{1}{r^2}

Here,

r = Distance from the source,

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

I_2 = I_1 \frac{r_1^2}{r_2^2}

I_2 = (0.10W/m^2)(\frac{(1m)^2}{(30m)^2})

I_2 = 1.11*10^{-4}W/m^2

Now the expression for the Area of ear drum is

A= \frac{\pi d^2}{4}

A = \frac{\pi (8.4mm\frac{1m}{10^3mm})^2}{4}

A = 5.5*10^{-5}m^2

The expression for Sound power is

P = AI_2

Replacing,

P= (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)

P = 6.1*10^{-9}W = 6.1*10^{-9}J/s

Therefore the energy reached per second is 6.1*10^{-9}J

4 0
3 years ago
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