Answer: The Electrostatic force of attraction or repulsion between two charges shows that the Newton's third law applies to electrostatic forces.
Explanation: Consider two Oppositely charged charges separated by distance d.
The electrostatic force exerted by charge 1 on charge 2 is.
By Coulomb's Law :
F1 = k
.....................................(1)
The electrostatic force exerted by charge 2 on charge 1 is.
F2 = - k
................................. (2)
negative sign shows that force are in opposite direction.
From Equation 1 and 2
F1 = - F2
Which implies Newton Third law.
Fg = G m₁ m₂ / r²
Fg = (6.67×10−¹¹) ( 70) ( 5.972×10²⁴) / (6.3781×10⁶)²
Fg = 685.43 N
Protons is 16 and Neutrons also 16
8.33 meters/sec. time = 30 sec. 30 sec. = 8.33 meters/sec.