Answer:
The magnitude of the force is 1.29*10^-3N in the positive x direction
Explanation:
In order to calculate the magnitude and direction of the force, you take into account that the force is the space derivative of the potential enrgy, as follow:
(1)
where:
You replace the expression for U into the equation (1) and solve for F:
![F(x)=-\frac{d}{dx}[Ax^4]=-4Ax^3](https://tex.z-dn.net/?f=F%28x%29%3D-%5Cfrac%7Bd%7D%7Bdx%7D%5BAx%5E4%5D%3D-4Ax%5E3)
(2)
The force on the particle, for x = -0.080m is:
The magnitude of the force is 1.29*10^-3N in the positive x direction
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction
1, 5 and 6 are the rocks your looking for, they make up the other ones on your list
Answer:
-150 N
Explanation:
(Newton's second law) F=ma
Sum of forces in Y direction= (+200 N)+(-200 N)= 0...
forces cancel, object does not accelerate up/down
Sum of forces in X direction= (+65 N)+(-65 N)+(-150 N)
= -150 N
notice that the +/- 65 components cancel, leaving a net force of 150 N in the LEFTwards direction (which is typically defined as negative)
Overall, the net force is -150 N
