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2 years ago

HELP ME PLEASE ASAP!!!!! WILL GIVE BRAINLIEST, FIVE STARS, AND HEART!!!!!(picture included)

Physics

2 answers:

aliina [53]2 years ago

4 0

Answer:

A goes with A B goes with B and C goes with C D goes with D and E goes with E i remember doing this so its correct i think

Explanation:

harina [27]2 years ago

3 0

Answer:

Kinetic - a box moving

Thermal - sand that feels warm

Electrical - lightning

Radiant - radio waves

Gravitational Potential - fruit hanging from a tree

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2 years ago

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a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro

finlep [7]

Answer:

$\theta=53.13^o$

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

$V_x=V_{ox}=V_ocos\theta$

$V_y=V_{oy}-gt=V_osin\theta-gt$

$x=V_{ox}t$

$\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}$

$\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}$

$\displaystyle y_{max}=\frac{V_{oy}^2}{2g}$

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

$x_{max}=3y_{max}$