Answer:
If a person selected at random from this group is a man, there is a 31.25% probability that the person favors raising the drinking age.
Step-by-step explanation:
We have these following informations:
There are 1000 people in total.
540 favored raising the age. Of them 390 were female, and 540-390 = 150 were male.
460 were opposed. Of them, 130 were female and 460-130 = 330 were males.
If a person selected at random from this group is a man, what is the probability that the person favors raising the drinking age?
There are 150+330 = 480 males. Of them, 150 favors raising the drinking age.
So

If a person selected at random from this group is a man, there is a 31.25% probability that the person favors raising the drinking age.
MON=RTS which is A because they are congruent so you just do the same thing they did for the first triangle.
Answer:
Quadrants 3 and 4
Step-by-step explanation:
we have


using a graphing tool
The solution is the triangular shaded area between the three dashed lines
see the attached figure
The solution lies in Quadrants 3 and 4
Answer:
2
Step-by-step explanation: