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3 years ago

Use quadratic formula to solve 1-6x^2-x

Mathematics

1 answer:

eduard3 years ago

6 0

Answer:

(3x-1)(2x+1)

Step-by-step explanation:

1-6x^2-x=0

-6x^2-x+1=0

6x^2+x-1=0

6x^2+(3-2)x-1=0

6x^2+3x-2x-1=0

3x(2x+1)-1(2x+1)=0

(3x-1)(2x+1)=0

So the factor is (3x-1)(2x+1)

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Look at photo (WITH THE PHOTO)

frez [133]

The answer to that would be 3/8

8 0

2 years ago

Read 2 more answers

The hourly median power (in decibels) of received radio signals transmitted between two cities

trasher [3.6K]

Using the lognormal and the binomial distributions, it is found that:

The 90th percentile of this distribution is of 136 dB.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.

There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.

In a lognormal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{\ln{X} - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = \sqrt{1.22}$

Question 1:

The 90th percentile is X when Z has a p-value of 0.9, hence X when Z = 1.28.

$Z = \frac{\ln{X} - \mu}{\sigma}$

$1.28 = \frac{\ln{X} - 3.5}{\sqrt{1.22}}$

$\ln{X} - 3.5 = 1.28\sqrt{1.22}$

$\ln{X} = 1.28\sqrt{1.22} + 3.5$

$e^{\ln{X}} = e^{1.28\sqrt{1.22} + 3.5}$

$X = 136$

The 90th percentile of this distribution is of 136 dB.

Question 2:

The probability is the p-value of Z when X = 150, hence:

$Z = \frac{\ln{X} - \mu}{\sigma}$

$Z = \frac{\ln{150} - 3.5}{\sqrt{1.22}}$

$Z = 1.37$

$Z = 1.37$ has a p-value of 0.9147.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.

Question 3:

10 signals, hence, the binomial distribution is used.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

For this problem, we have that $p = 0.9147, n = 10$ , and we want to find P(X = 6), then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.9147)^{6}.(0.0853)^{4} = 0.0065$

There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.

You can learn more about the binomial distribution at brainly.com/question/24863377

5 0

2 years ago

−4 4/5 ÷ 4 A. -1 1/5 B. -4/5 C. 4/5 D. 1 1/5

kogti [31]

Answer:

A. -1⅕

Step-by-step explanation:

$-4\frac{4}{5}\div 4 = -4,8\div 4 = -1,2 = -1 \frac{1}{5}$

I am joyous to assist you anytime.

7 0

3 years ago

Which expression is equivalent to

givi [52]

Answer:

$\boxed{D. 9x + 36}$

Step-by-step explanation:

Hey there!

Given info

9(x + 4)

Solve!

9*x = 9x

9*4 = 36

Answer

9x + 36

D. 9x + 36

Hope this helps :)

6 0

3 years ago

Read 2 more answers

PLS HELP ASAP!! WILL MARK BRAINLYIST

son4ous [18]

Answer:

$39,851.25

Step-by-step explanation:

If the sales increase at a rate of 9% per year, this means it will be 109% of the previous year's value since 100% + 9% = 109%

109% in decimal form = 109/100 = 1.09

Therefore, the exponential function is:

$y = 20000 \cdot 1.09^x$ , where $x$ is the number of years

So when $x=8$ ,

$y = 20000 \cdot 1.09^8=39851.252...$

After 8 years, annual sales = $39,851.25

7 0

2 years ago

Use quadratic formula to solve 1-6x^2-x​

Use quadratic formula to solve 1-6x^2-x