Use quadratic formula to solve 1-6x^2-x
1 answer:
Answer:
(3x-1)(2x+1)
Step-by-step explanation:
1-6x^2-x=0
-6x^2-x+1=0
6x^2+x-1=0
6x^2+(3-2)x-1=0
6x^2+3x-2x-1=0
3x(2x+1)-1(2x+1)=0
(3x-1)(2x+1)=0
So the factor is (3x-1)(2x+1)
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