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babunello [35]
3 years ago
6

Helppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Leona [35]3 years ago
5 0

Answer: 3

Step-by-step explanation:

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Factor.<br> F2 + 3f - 4<br> What’s the answer
sp2606 [1]

Answer:

9f I think your welcome

4 0
4 years ago
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the ratio of adults to children attending a new exhibit st the museum was found to be 8:5. Based on this ratio if 390 people att
Natali5045456 [20]
First, you add the two parts of the ratio together. 8+5=13. Then you do 390 divided by 13 which is 30. After this, you multiply 30 by each side to get the ratio to be equal. 30x8=240, and 30x5=150. This can now be put into the ratio 240:150. As you said it was in the ratio adults to children, it must stay in that order. The part of the ratio for children is 150. 
<em>The answer to your question is 150. You can double-check your answer by adding up the two parts again. 240=150=390 so you can be assured that your answer is truly correct. Thank you for uploading this question. I hope my explanation was helpful enough for you
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<em><u>PencilandPaper21</u></em>
7 0
3 years ago
Im working on algebra hw and i need help with this problem 8.1x - 4.5y = 5.4
alexira [117]
8.1x - 4.5y = 5.4.....subtract 8.1x from both sides
-4.5y = -8.1x + 5.4...divide both sides by -4.5
y = (- 8.1/-4.5)x + 5.4 / -4.5...simplify
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7 0
4 years ago
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The following describes a sample. The information given includes the five number summary, the sample size, and the largest and s
lys-0071 [83]

Answer:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

IQR = Q_3 -Q_1 = 250-210 =40

For this case we need to find the lower and upper limit with the following formulas:

L= Q_1 - 1.5*IQR = 210 -1.5*40 =150

U= Q_3 + 1.5*IQR = 250 +1.5*40 =310

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0
4 years ago
I NEED ANSWER ASAP!!!! AND PLEASE GIVE ANSWER ACCORDING TO THE GRAPH BELOW :)))
podryga [215]

Answer:

ok so put one point on (0, 1) and another on (3, -3)

brainliest pls :)

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3 years ago
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