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2 years ago

6

A survey at your school found that 842 in 989 students have a cell phone. What percent of the student in school has a cell phone

? Round to the nearest hundredth where necessary

2 answers:

Mumz [18]2 years ago

8 0

Answer:

85.14% of the students have a cell phone.

True [87]2 years ago

6 0

84.14% have the cell phones when necessary

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8) Find the x-intercepts: *

postnew [5]

Answer:

c ok thanks

Step-by-step explanation:vvtwe

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2 years ago

Can somebody help me with this problem. And make sure that u can explain how to do it don't just give me the answer.

Tpy6a [65]

Answer:

x=50

Step-by-step explanation:

Look at the triangle as a whole. This is a 30-60-90 triangle by speculation. You can see that the hypotenuse is equal to 100. By using sine (you can use cosine as well) , you get the expression, "(sin 30 degrees) = x/100" since sin is the opposite side over the hypotenuse. Do some basic trigonometry to get "1/2 = x/100". By now, you should know that 50/100 is the same as 1/2.

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2 years ago

Can someone explain why the ans is X=6? Its (x-6)

andrew-mc [135]

Answer:

because either x-6=0 or x+1=0

x-6=0

x=0+6

x=6 OR,

x+1=0

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x=-1

Step-by-step explanation:

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2 years ago

Based on the survey results from 300 selected students in the Burbank School District (BSD), the 98% confidence interval used to

Pavlova-9 [17]

Answer:

follows are the solution to this question:

Step-by-step explanation:

Please find the correct question in the attached file:

The formula for calculating the Confidence interval of proportion:

$\to CI=\hat{p} \pm Z_{\frac{\alpha}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\\to \hat{p}=\frac{\text{lower limit +upper limit}}{2}\\$

$=\frac{0.48+0.60}{2}\\\\=\frac{1.08}{2}\\\\=0.54$

The number of learners with access to working at home on a computer:

$= 0.54 \times 300 \\\\=162$

Lower limit =0.48

upper limit = 0.60

$\to margin \ error = \frac{\text{upper limit - lower limit}}{2}\\$

$=\frac{0.60-0.48}{2}\\\\=\frac{0.12}{2}\\\\= 0.06$

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3 years ago

In Mr Tarkiainens each student chooses two of the topics listed in the chart above for their papers how many different pairs can

elena-s [515]

The answer is 90 different pairs.
So if there are 10 topics and each will get 9 pairings , so the over all pairs you will get is 90.

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3 years ago