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4 years ago

Andrew solved the following inequality, and his work is shown below:

Mathematics

1 answer:

sleet_krkn [62]4 years ago

3 0

The answer is b because when you divide or multiply by a negative you're supposed to flip the sign .

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A student is running a 5-kilometer race. He runs 1 kilometer every 3 minutes. Select the function that describes his distance fr

Phantasy [73]

D = distance from finish line

D= 5 - 1/3x

Distance from the finish line is equal to the distance of the start line from the finish line, minus one third of a km times the number of minutes hes been running.

using given variables; D= 5 - 1/3*3
D=5-3/3
D=5-1
D=4

7 0

4 years ago

Read 2 more answers

Y = 2x <br> x + y = −6<br> the answer should be like this (x,y) or ( , )

melisa1 [442]

Answer:

(-2, -4)

Step-by-step explanation:

Given:

The system of equations to solve is given as:

$y=2x\\\\x+y=-6$

In order to solve this system of linear equations, we use substitution method.

In substitution method, we substitute the value of any one variable in the other equation.

So, we substitute the value of 'y' from first equation in the second equation.

This gives,

$x+2x=-6\\\\3x=-6$

Dividing both sides by 3, we get:

$\frac{3x}{3}=\frac{-6}{3}\\\\x=-2$

Now, $y=2x=2\times -2=-4$

Therefore, the solution is (-2, -4)

6 0

4 years ago

A Ferris wheel has a radius of 10 m, and the bottom of the wheel passes 1 m above the ground. If the Ferris wheel makes one comp

Morgarella [4.7K]

Answer:

$y = 11 - 10cos(0.1\pi t)$

Step-by-step explanation:

Suppose at t = 0 the person is 1m above the ground and going up

Knowing that the wheel completes 1 revolution every 20s and 1 revolution = 2π rad in angle, we can calculate the angular speed

2π / 20 = 0.1π rad/s

The height above ground would be the sum of the vertical distance from the ground to the bottom of the wheel and the vertical distance from the bottom of the wheel to the person, which is the wheel radius subtracted by the vertical distance of the person to the center of the wheel.

$y = h_g + d_b = h_g + R - d_c$ (1)

where $h_g = 1$ is vertical distance from the ground to the bottom of the wheel, $d_b$ is the vertical distance from the bottom of the wheel to the person, R = 10 is the wheel radius, $d_c$ is the vertical distance of the person to the center of the wheel.

So solve for $d_c$ in term of t, we just need to find the cosine of angle θ it has swept after time t and multiply it with R

$d_c = Rcos(\theta(t)) = Rcos(\omega t) = 10cos(0.1\pi t)$

Note that $d_c$ is negative when angle θ gets between π/2 (90 degrees) and 3π/2 (270 degrees) but that is expected since it would mean adding the vertical distance to the wheel radius.

Therefore, if we plug this into equation (1) then

$y = h_g + R - d_c = 1 + 10 - 10cos(0.1\pi t) = 11 - 10cos(0.1\pi t)$