All categories

2 years ago

A line that includes the point (10, 0) has a slope of

Mathematics

1 answer:

Sergeu [11.5K]2 years ago

4 0

9514 1404 393

Answer:

y = 1/5x -2

Step-by-step explanation:

When a point and slope are given, sometimes it is easiest to start with the point-slope form of the equation. Then it can be rearranged to the desired form.

y -k = m(x -h) . . . . . line with slope m through point (h, k)

y -0 = 1/5(x -10) . . . . . line with slope 1/5 through point (10, 0)

y = 1/5x -2 . . . . . . . eliminate parentheses to get slope-intercept form

_____

Note that the slope in the attached picture is 1/5, but your problem text says it is 5. Very different equations will result from these different slopes.

You might be interested in

The floor of the commons room at King Middle School is in the shape of a square with side lengths of x^2 y^3 feet. New tile is g

umka2103 [35]

The useful hint here is the shape of the area which is square. By definition, a square is a two-dimensional figure that consist of two parallel sides have the same equal measure. The only given dimension of a square is its side. The area is equal to the square of the side. Since the side has a measure of x²y³,

A = s² = (x²y³)²
By the laws of exponents, for this problem, just simply distribute the outer exponent to each of the inner exponent.
A = x⁴y⁶

8 0

2 years ago

Carla has a bookcase with 4 shelves.she puts 6 bears in a row on each shelf. How many bears does she have? Draw a picture and wr

N76 [4]

How does a bear fit on a shelf?

3 0

2 years ago

Given g(x)<br><img src="https://tex.z-dn.net/?f=g%28x%29%20%3D%200.3%20%7Bx%7D%5E%7B2%7D%20%20%2B%2052" id="TexFormula1" title="

horsena [70]

Answer:

no solution

Step-by-step explanation:

5 0

2 years ago

16. Solve -3x2 - 9x + 12 = 0.

AURORKA [14]

Given :

-3x² - 9x + 12 = 0

To find :-

Value of x .

Solution :-

Given equation ,

-( 3x² + 9x -12 ) = 0
3x² + 9x - 12 = 0
3x² + 12x - 3x - 12 = 0
3x ( x +4) -3( x +4) = 0
(3x -3)(x +4) = 0
x = 3/3 , -4
x = 1 , -4

7 0

2 years ago

-/2 points

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

2 years ago