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stira [4]
3 years ago
13

Can someone solve these and thank YOU

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0

Answer:

a is 1.8

b is 5

c is 1/2

d is 8/21

Step-by-step explanation:

a 13/7 is 1.8 rounded

b 5/1 is 5

c 1/2 have to add a 1

d 2*8 is 16 the 16+5 is 21 then flip it which is 8/21

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Use distributive property. 4 x 63 = ??
aleksandrvk [35]

Answer:

(4) * (63)

252

(* ̄3 ̄)╭

4 0
3 years ago
If Elisa gets an allowance of $35 per week and spends $10 of it on food and drink, $5 on entertainment and $5 on miscellaneous t
Maslowich

Answer:

15$

Step-by-step explanation:

35-10=25$

25-5=20$

20-5=15$

6 0
4 years ago
Samantha plays a trivia game. She earns 3 points for each
Rudiy27

この質問は緒と面白いね

11x3=33

33-4x0.75=30

頑張ってね!

5 0
2 years ago
If f(x) = 2x – 6 find f(7) - 9. *
evablogger [386]

Answer:

-1

Step-by-step explanation:

Plug 7 in for wherever there's an "x."

f(x) = 2(7) - 6

f(x) = 14 - 6

f(x) = 8

Now subtract 9 from 8.

8 - 9 = -1

6 0
3 years ago
Susie’s Sweet Shop sells chocolate boxes that contain three types of chocolate truffles: solid chocolate truffles, cream center
olganol [36]

Let us make a list of all the details we have

We are given

The cost of each solid chocolate truffle = s

The cost of each cream centre chocolate truffle = c

The cos to each chocolate truffle with nuts = n

The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25

That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)

The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75

That is 10s+5c+10n = $68.75

The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00

That is 12s+12n=$66.00

Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.



6 0
3 years ago
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