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melomori [17]
3 years ago
15

Write 2,13×10^-3 in decimal form​

Mathematics
1 answer:
ipn [44]3 years ago
4 0

Answer:

2,13×10^-3

213×1/10^3; express to positive product

213/10^3; calculate

213/1000; evaluate

=0.213

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Write 7.12 as a mixed number in simplest form.
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Answer:

7 3/25

Step-by-step explanation:

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Every morning Calvin reads for 15 minutes. Every evening he reads for n minutes. Next week, he is going to triple the amount of
prohojiy [21]
Answer:
15 + 3n

Triple the amount of evening which is “n” so it would “3n”

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Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
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Answer:

blank=x=84

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Answer:

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Step-by-step explanation:

13(13-3)/2 = 65 diagonals.

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