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3 years ago

What is the value of the expression (36 1/2)^2

1 answer:

4 0

324 is the answer to your promblem welcome

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Luden [163]

Given:

In a two-digit number, the tens digit is 5 less than the units digit.

The number itself is five more than three times the sum of its digits.

To find:

The number.

Solution:

Let the two digit number is ab. So,

$ab=10a+b$

Tens digit is 5 less than the units digit.

$a=b-5$ ...(i)

The number itself is five more than three times the sum of its digits.

$10a+b=3(a+b)+5$

$10a+b=3a+3b+5$

$10a+b-3a-3b=5$

$7a-2b=5$ ...(ii)

Using (i) and (ii), we get

$7(b-5)-2b=5$

$7b-35-2b=5$

$5b=5+35$

$5b=40$

$b=8$

Putting b=8 in (i), we get

$a=8-5$

$a=3$

Therefore, the required number is 38.

5 0

3 years ago

MArishka [77]

Answer:

x = 2

Step-by-step explanation:

10x + 1 = 2(3x + 5) - 1

mutlipy the 2 to the 3x and the 5
you should get 10x + 1 = 6x + 10 - 1
now you have to add the combine terms
so it will now be 10x + 1 = 6x + 9
now you.have to get the x's on one side and the constants (numbers alone) on the other side
so you can subtract the 6x on both sides
once you do that you wil get 4x + 1 = 9
After you get this equation you will have to subtract the one from both sides.
you will get 4x = 8
All you have to do it divide 4 on both sides. Your final answer is x = 2.