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2 years ago

6

Together,Ella and Ola have 70 mushrooms.9 of Ella's mushrooms are brown and 17 of Ola's mushrooms are white.How many mushrooms d

oes Ella have?

1 answer:

Aliun [14]2 years ago

5 0

Answer:

why does this make my brain hurt

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What is the distance between the points (7,-6) and (13,2)? Please show all work.

lana [24]

Answer:

Step-by-step explanation:

(7,-6) (13,2)

2--6. 8. 4

------= ------= ------ (2--6 turns to a +)

13-7. 6. 3

4

Slope:------

3

Points=(7,-6)

4

y--6=----(x-7) (y--6 turns to a +)

3

4. 28

y+6= ---- x - ----

3. 3

-6. -6

-------------------------

4. 46

y=----- x - -------

3. 3

6 0

2 years ago

In a certain chemical, the ratio of zinc to copper is 3 to 14. A jar of the chemical contains 658 grams of copper. How many gra

Natasha_Volkova [10]

Answer:

hehehehehheh

Step-by-step explanation:

Shiny roachnoises :P

5 0

2 years ago

What is the solution set for 5x−5=15, given the replacement set {0, 1, 2, 3, 4}?

True [87]

Answer:

x=4

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

2 years ago

Jillian flew to New Zealand for summer vacation. While she was there, she rode her bike 1/3 of the time. She spent 1/4 of the re

Elis [28]

If the time she rode her bike is 24, then 24*3 would be the Whole time she was there. She was there for a total of 72 hours.
Subtract 24 from 72 because it's 1/3 and you need the other time.
You get 48.
You need to find 1/4 of 48, so you divide it by 4.
48/4 = 12.
She rides the train for 12 hours. This is 1/2 of a day, so your answer is:

She rides the train for 1/2 of a day.

7 0

3 years ago