<span><span>1.
</span>Given Data:
=> There are a total of 8 paper clips
=> There are also 4 erasers
=> And there are 6 thumbtacks.
Now, answer the following question
=> The number of paper clips is _____ the number of erasers
Let’s compare
There are 8 paper clips and 4 erasers.
Thus the number of paper clips is twice the number of erasers.
=> The number of erasers is ___ the number of thumbtacks>
There are 4 erasers and 6 thumbtucks.
Thus the number of erasers is 2/3 the number of thumbtucks </span>
The answer would be 9 you would add the 13 and 7 then have 20-5t=-25 then subtract 20 from 25 then you would have -5=-45 which is 9
The polynomial is not factorable, so use the quadratic formula.
y^2 + 8y + 19 = 0
x = (-b +- sqrt(b^2 - 4ac))/(2a)
x = (-8 +- sqrt(8^2 - 4(1)(19))/(2 * 1)
x = (-8 +- sqrt(64 - 76))/2
x = (-8 +- sqrt(-12))/2
If you have not learned imaginary/complex numbers, then the answer is "No solution" since there is no real number solution.
If you have learned imaginary/complex numbers, then we'll continue.
x = (-8 +- 2i sqrt(3))/2
x = -4 +- i sqrt(3)
According to the probles represented above, there is addition of two angles which makes it totally clear. I am pretty sure that the answer with the actual reason of this task is the second option <span>B. Angle Addition Postulate, as you can see a couple of new angles in there :)
Regards!</span>
