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11111nata11111 [884]
3 years ago
15

The initial temperature of a cup of tea is 200ºF. The surrounding temperature is 70ºF, and the value of the constant k is 0.6. A

pplying Newton's cooling model, the temperature of the tea after 2 hours will be ºF
Mathematics
1 answer:
Mazyrski [523]3 years ago
8 0
Newton's cooling model is ΔT = ΔTo * e ^ (-k t)

ΔTo = 200°F - 70°F = 130°F

k = 0.6

t = 2 hours

=> ΔT = 130 * e ^ (-0.6 t) = 130 * e^ (-0.6 * 2) = 130 * e ^ (-1.2)

ΔT = 39.15°F

ΔT = T - Tenvironment => T = ΔT + Tenvironment = 39.15°F + 70°F = 109.15°F ≈ 109 °F.

Answer: T = 109 °F


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Answer:

-12

Step-by-step explanation:

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If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
s344n2d4d5 [400]
From the first equation
6x - y = 1
6x - y - 1 = 0
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Substituting we get
4x - 3(6x - 1) = -11
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2 years ago
HELP PLEASE ILL GIVE YOU BRAINLIST !! I DONT UNDERSTAND IT .
inn [45]

Step-by-step explanation:

35 + 35 = 70

180 - 70 = 110

180 - 110 = 70

70  + 70 = 140

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7 0
3 years ago
A closed container has 5.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10−24 grams.
MatroZZZ [7]

Answer:

The correct option is the last one (0,84 grams, because (5.04 × 1.67) × (10^23 x 10^-24) = 8.4168 x 10^-1))

Step-by-step explanation:

The first step is to think that you have to multiply the number of atoms for the weight of each atom.

When you work with scientific notation, you should solve the operation for numbers and for the ten base. In this case you solve 5.04 x 1.67 and then the product of the ten bases. For this product you have to sum the exponents of the ten base 23 + (-24) = -1.

Summarizing.... 5.04 x 10^23 x 1.67 x 10^-24 = (5.04 x 1.67) x (10^23x10^-24)  ⇒ 5.04 x 10^23 x 1.67 x 10^-24 = 8.4168 x 10^-1

⇒ 5.04 x 10^23 x 1.67 x 10^-24 = 0,84168.

4 0
3 years ago
un solar tiene forma de 3/4 de círculo unido con un triángulo rectángulo , En este solar va a ser utilizado para sembrar clavele
Stolb23 [73]

Answer:

$1092671.191

Step-by-step explanation:

<u>Cálculo de Areas</u>

El área de un círculo de radio r se obtiene con la fórmula:

A_c=\pi r^2

El área de un triángulo de base b y altura h, perpendicular a la base es:

A_t=\frac{bh}{2}

Si el triángulo es rectángulo, b y h son los catetos

El solar tiene una forma tal como se ilustra en la figura anexa. Para averiguar el costo del abono y del techo, debe calcularse primero el área total a cultivar. Primero se determina el área de 3/4 de círculo de radio 5.9 metros

A_c=\frac{3}{4}\pi r^2

A_c=\frac{3}{4}\pi (5.9)^2

A_c=82.0191302\ m^2

Por su parte, el triángulo mostrado, tiene ambos catetos iguales al radio de círculo, por lo que su área será

A_t=\frac{r^2}{2}

A_t=\frac{(5.9)^2}{2}

A_t=17.405\ m^2

El área total del solar es la suma de ambas:

A_s=82.0191302\ m^2+17.405\ m^2

A_s=99.4241302\ m^2

El metro cuadrado de abono cuesta $8016. El costo de abono es

C_a=99.4241302\ m^2*8016=\$796983.8277

El metro cuadrado de techo cuesta $2974. El costo del techo es

C_t=99.4241302\ m^2*2974=\$295687.3632

El costo total es la suma de los dos anteriores:

Total=\$796983.8277+\$295687.3632

Total=\$1092671.191

El valor total a intervenir para la adecuación del solar es $1092671.191

7 0
3 years ago
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