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Vlad [161]
3 years ago
9

There are 35 tables at the wedding. The tables can be lined up in equal-sized rows. Which list shows all the possibilities for t

he number of tables
Mathematics
2 answers:
algol133 years ago
7 0

Answer:

They can be lined up in 7 groups of 5.

Or in 5 groups of 7.

labwork [276]3 years ago
4 0

Answer:

3 rows

Step-by-step explanation: because 3

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Hi there!

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Use slope formula to solve for the slope of the line:

slope = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

Plug in points into the equation. We can use the points (0, -10) and (25, -5):

slope = \frac{-5-(-10)  }{25 -0 } = \frac{5}{25} = \frac{1}{5}

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Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:
Phoenix [80]

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find  how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

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With 4/5 per day , for 14 days :

⇒ 14(\frac{4}{5} )

⇒ 14(0.8 )

⇒ 11.2

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ 14(1.25 )

⇒ 17.5

Subtracting Maria's - Trenton's :

⇒ 17.5-11.2=6.3

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

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3 years ago
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xxMikexx [17]

Answer:

B, 224in2

It may get tedious but just find the area of each face and write them down

Step-by-step explanation:

6 0
3 years ago
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