1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vikentia [17]
3 years ago
9

Exclain why 0.32 with a line above it is greater than 0.32

Mathematics
1 answer:
ella [17]3 years ago
6 0
"0.32 with a line above it" could refer to two possible numbers, either 0.\overline{32}=0.323232\ldots or 0.3\overline2=0.3222\ldots.

In either case, 0.32 will be the smaller of the two numbers simply because it terminates with two digits after the decimal point, while the others keep going, basically adding a small positive number to 0.32.
You might be interested in
Who is the protagonist?
Elena-2011 [213]
Alladin because it’s a name
8 0
3 years ago
Read 2 more answers
Out of 8 boys and 6 girls in a high school, a team of seven students is selected. What is the probability that three boys and fo
maria [59]
The probabitily is if they get selected  as a team of 7 aswell if they're playing a game of some sort.
 
7 0
3 years ago
Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a
kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be representedh(t)=-16t^2+20t.

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?  

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}

\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}

\text{Average rate of change}=\frac{6}{\frac{1}{2}}

\text{Average rate of change}=\frac{2\cdot 6}{1}

\text{Average rate of change}=12

Therefore, Spot's average rate of ascent is 12 feet per second.

3 0
3 years ago
CS Algebra
CaHeK987 [17]

Answer:

Hope this helps :)

Step-by-step explanation:

8(x - 2) = 2x + 8

y+9 = -2(y + 1)

value of x in 8(x - 2) = 2x + 8

x=4

substitue

y+9=−2(y+1)

value of y y+9=−2(y+1)

y= - 11/3 or 3.66...

x=4

y=4 (I rounded 3.66)

4 0
3 years ago
What is the median distance jumped 7.48, 7.60, 7.15, 7.44, 7.73, 7.72
irga5000 [103]
It would be 7.54 because you fist have to put the numbers ordered smallest to biggest amount 7.15, 7.44, 7.48,7.60, 7.72, 7.73 so the numbers that are in the middle are 7.48 and 7.60 you add them up, and the result you divide by 2 which gives you 7.54.
3 0
3 years ago
Other questions:
  • The sum of two numbers is 30.the first number is 1/5 of the second number. what are the numbers?
    15·1 answer
  • Showing statements are true of the graph of the function F(x)= (x+5) (x-3)
    11·1 answer
  • If 2 objects cost 40 dollars how much would 7 objets cost?
    11·2 answers
  • Which variable is likely to be linked to both of the variables mentioned in this statement?
    11·1 answer
  • What are the answers
    8·2 answers
  • What is the constant of variation?​
    9·2 answers
  • Given the table, how can you use a graph to find additional equivalent ratios? x y 2 3 4 6 Plot the ordered pairs (2, 3) and (4,
    5·2 answers
  • How can I write this out?
    5·1 answer
  • Please help me with this question I’m doing points
    9·2 answers
  • ms.watson earns more than $24 per hour. The inequalit x>24 represent the situation.which statement best represent the solutio
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!