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Vikentia [17]
3 years ago
9

Exclain why 0.32 with a line above it is greater than 0.32

Mathematics
1 answer:
ella [17]3 years ago
6 0
"0.32 with a line above it" could refer to two possible numbers, either 0.\overline{32}=0.323232\ldots or 0.3\overline2=0.3222\ldots.

In either case, 0.32 will be the smaller of the two numbers simply because it terminates with two digits after the decimal point, while the others keep going, basically adding a small positive number to 0.32.
You might be interested in
Sharon has a new beaded necklace. 72 out of the 80 beads on the necklace are blue. What
erma4kov [3.2K]

Answer:

Sharon bought a necklace with 90% blue beads.

Step-by-step explanation:

We are given that Sharon's necklace has 80 beads. We are also given that of those 80 beads, 72 of them are blue.

Therefore, we can set up a ratio of blue beads to total beads in order to find out the relationship.

\displaystyle \frac{72}{80}=\frac{36}{40}=\frac{18}{20}=\frac{9}{10}

Then, using the fraction we receive as a result, we can convert this to a decimal.

\displaystyle \frac{9}{10} = 0.9

After we complete this calculation, we can multiply our decimal by 100 in order to obtain the relationship in percentage form.

0.9 \times 100 = 90\%

Of the 80 beads, 90% were blue beads.

4 0
3 years ago
Read 2 more answers
Part A: Joel uses the incorrect expression 0.95(190)(0.8) to calculate that the computer will cost him a total of $144.40. Descr
UkoKoshka [18]

Complete question:

Joelwants to buy a new tablet computer from a store having a 20% off sale on all tablet. The tablet he wants has an original cost of $190. He also wants to make sure he has enough money to pay the 5% sales tax.

Answer:

$159.60

Step-by-step explanation:

Given the following :

Sales tax = 5%

Percentage discount = 20%

Original cost = $190

Joel's incorrect expression : 0.95(190)(0.8)

Joel's mistake is the 0.95 which is equivalent to 95% used in Calculating the total cost of the computer. The sales tax increases the total cost of the computer and instead of subtracting 5% sales tax, it should be added.

B.) 20% discount = 0.2 will be deducted from 100%(1)

1 - 0.2 = 0.8

5% sales tax = 0.05 will be added :

1 + 0.05 = 1.05

Original cost = $190

Therefore,

Total cost : Original cost * sales tax * discount

Total cost = $190 * 1.05 * 0.8

Total cost = $159.60

6 0
3 years ago
Quick algebra 1 question for 10 points!
Maslowich

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

<h3>What is the range of a quadratic equation?</h3>

In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.

x = - 9

y = (2 / 3) · (- 9)² - 6

y = 48

x = - 6

y = (2 / 3) · (- 6)² - 6

y = 18

x = - 3

y = (2 / 3) · (- 3)² - 6

y = 0

x = 0

y = (2 / 3) · 0² - 6

y = - 6

x = 3

y = (2 / 3) · 3² - 6

y = 0

x = 6

y = (2 / 3) · 6² - 6

y = 18

x = 9

y = (2 / 3) · 9² - 6

y = 48

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

To learn more on functions: brainly.com/question/12431044

#SPJ1

7 0
1 year ago
HELP ME OUT PLEASE!!!!!!!
masha68 [24]

Answer:

option C is correct.

according to me..

hope it helpful for you.

3 0
2 years ago
A random sample of n = 64 observations is drawn from a population with a mean equal to 20 and standard deviation equal to 16. (G
dezoksy [38]

Answer:

a) The mean of a sampling distribution of \\ \overline{x} is \\ \mu_{\overline{x}} = \mu = 20. The standard deviation is \\ \frac{\sigma}{\sqrt{n}} = \frac{16}{\sqrt{64}}=2.

b) The standard normal z-score corresponding to a value of \\ \overline{x} = 16 is \\ Z = -2.

c) The standard normal z-score corresponding to a value of \\ \overline{x} = 23 is \\ Z = 1.5.

d) The probability \\ P(\overline{x}.

e) The probability \\ P(\overline{x}>23) = 1 - P(Z.

f)  \\ P(16 < \overline{x} < 23) = P(-2 < Z < 1.5) = P(Z.

Step-by-step explanation:

We are dealing here with the concept of <em>a sampling distribution</em>, that is, the distribution of the sample means \\ \overline{x}.

We know that for this kind of distribution we need, at least, that the sample size must be \\ n \geq 30 observations, to establish that:

\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})

In words, the distribution of the sample means follows, approximately, a <em>normal distribution</em> with mean, \mu, and standard deviation (called <em>standard error</em>), \\ \frac{\sigma}{\sqrt{n}}.

The number of observations is n = 64.

We need also to remember that the random variable Z follows a <em>standard normal distribution</em> with \\ \mu = 0 and \\ \sigma = 1.

\\ Z \sim N(0, 1)

The variable Z is

\\ Z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}} [1]

With all this information, we can solve the questions.

Part a

The mean of a sampling distribution of \\ \overline{x} is the population mean \\ \mu = 20 or \\ \mu_{\overline{x}} = \mu = 20.

The standard deviation is the population standard deviation \\ \sigma = 16 divided by the root square of n, that is, the number of observations of the sample. Thus, \\ \frac{\sigma}{\sqrt{n}} = \frac{16}{\sqrt{64}}=2.

Part b

We are dealing here with a <em>random sample</em>. The z-score for the sampling distribution of \\ \overline{x} is given by [1]. Then

\\ Z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{16 - 20}{\frac{16}{\sqrt{64}}}

\\ Z = \frac{-4}{\frac{16}{8}}

\\ Z = \frac{-4}{2}

\\ Z = -2

Then, the <em>standard normal z-score</em> corresponding to a value of \\ \overline{x} = 16 is \\ Z = -2.

Part c

We can follow the same procedure as before. Then

\\ Z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{23 - 20}{\frac{16}{\sqrt{64}}}

\\ Z = \frac{3}{\frac{16}{8}}

\\ Z = \frac{3}{2}

\\ Z = 1.5

As a result, the <em>standard normal z-score</em> corresponding to a value of \\ \overline{x} = 23 is \\ Z = 1.5.

Part d

Since we know from [1] that the random variable follows a <em>standard normal distribution</em>, we can consult the <em>cumulative standard normal table</em> for the corresponding \\ \overline{x} already calculated. This table is available in Statistics textbooks and on the Internet. We can also use statistical packages and even spreadsheets or calculators to find this probability.

The corresponding value is Z = -2, that is, it is <em>two standard units</em> <em>below</em> the mean (because of the <em>negative</em> value). Then, consulting the mentioned table, the corresponding cumulative probability for Z = -2 is \\ P(Z.

Therefore, the probability \\ P(\overline{x}.

Part e

We can follow a similar way than the previous step.

\\ P(\overline{x} > 23) = P(Z > 1.5)

For \\ P(Z > 1.5) using the <em>cumulative standard normal table</em>, we can find this probability knowing that

\\ P(Z1.5) = 1

\\ P(Z>1.5) = 1 - P(Z

Thus

\\ P(Z>1.5) = 1 - 0.9332

\\ P(Z>1.5) = 0.0668

Therefore, the probability \\ P(\overline{x}>23) = 1 - P(Z.

Part f

This probability is \\ P(\overline{x} > 16) and \\ P(\overline{x} < 23).

For finding this, we need to subtract the cumulative probabilities for \\ P(\overline{x} < 16) and \\ P(\overline{x} < 23)

Using the previous <em>standardized values</em> for them, we have from <em>Part d</em>:

\\ P(\overline{x}

We know from <em>Part e</em> that

\\ P(\overline{x} > 23) = P(Z>1.5) = 1 - P(Z

\\ P(\overline{x} < 23) = P(Z1.5)

\\ P(\overline{x} < 23) = P(Z

\\ P(\overline{x} < 23) = P(Z

Therefore, \\ P(16 < \overline{x} < 23) = P(-2 < Z < 1.5) = P(Z.

5 0
2 years ago
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