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Aliun [14]
3 years ago
10

PLS ANSWER IN 5 MINS I WILL MARK BRAINLIEST THE QUESTION IS IN THE PICTURE I ATTACHED

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

\frac{19}{14}x + \frac{97}{56} =

^^^hope this helps! :)

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HELP PLEASE!!! CLUELESS
statuscvo [17]
-3-8X≥9

Add 3 on both sides.

-8X≥12

Divide by negative 8 and flip the sign.

X≤-1.5

There isn't a number behind five, so I would just keep as is.

I hope this helps!
~kaikers
5 0
3 years ago
Find simple interest on $5,523 principal deposited for seven years at a rate of 4.99%
Whitepunk [10]
I=PRT
I=interest
P=initial amount
R=rate in decimal
T=time in years

given
P=5523
R=4.99%=0.0499
T=7

I=(5523)(0.0499)(7)
I=1929.1839
round

$1929.18 interest earned
8 0
3 years ago
Read 2 more answers
Find the points on the cone z2 = x2 + y2 that are closest to the point (6, 2, 0).
aliya0001 [1]

Answer:

The closest points on the cone are;

(6, 2, -√10) and (6, 2, √10)

Step-by-step explanation:

Let B(x, y, z) denote a point on the cone.

Therefore, the distance between the points (6, 2, 0) and B(x, y, z) is;

d = √[(x - 6)² + (y - 2)² + (z - 0)²]

d = √[(x - 6)² + (y - 2)² + z²]

Since we are given that z² = x² + y², we now have;

d = √[(x - 6)² + (y - 2)² + x² + y²]

Taking the square of both sides gives;

d² = [(x - 6)² + (y - 2)² + x² + y²]

x² is an increasing function. Thus, minimizing d is also the same as to minimize f (x, y) = d²

Thus, f' = 0. So;

df/dx = 2(x - 6) + 2x = 0

2x - 12 + 2x = 0

4x = 12

x = 12/4

x = 3

Similarly,

df/dy = 2(y - 2) + 2y = 0

2y - 4 + 2y = 0

4y - 4 = 0

4y = 4

y = 4/4

y = 1

Now,from earlier;

z² = x² + y²

Thus;

z = ±√(3² + 1²)

z = ±√10

Thus, the closest points on the cone are;

(6, 2, -√10) and (6, 2, √10)

7 0
3 years ago
Find the area of a circle with diameter 10 .
andriy [413]
The answer is 78.54.

5 0
3 years ago
Can someone please help me
MaRussiya [10]

Answer:

The answer is B)

Step-by-step explanation:

Use the Distance Formula

d = sqr(1 + 3)^2 + (0 - 4)^2

d = sqrt(32)

d = 4*sqrt(2)


7 0
3 years ago
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