Consider c as the cost of the widget so that our given equation is
c = 0.1w^2 + 20w
Take the derivate of the equation.
d/dt (c = 0.1w^2 + 20w)
dc/dt = 0.2w + 20
Given dc/dt = $16000 per month, the number of widgets would contain:
16000 = 0.2w + 20
-0.2w = 20 - 16000
-0.2w = -15980
w = 79900 widgets
Answer:
Step-by-step explanation:
1300 x 1.042 = $1354.6
Median: Put the list in order from least to greatest.
$20, $20, $23.50, $25, $26.50
$20, $23.50, $25
$23.50 is the median. I took one from each side until I had one left.
Mean: Get the sum of them all and then divide by the number of earnings ( in this case )
$25 + $26.50 = $51.50 $51.50 + $20 = $71.50 $71.50 + $23.50 = $95
$95 + $20 = $115 $115/5 = $23
$23 is the mean.
Mode: Is the one that finds the frequency or in lamen terms it is the number which appears most often.
There's no steps for finding the expect counting how many times that number appeared.
$20 is the mode.
Answer: 45.725 ( i think)
Step-by-step explanation: 2.325 + 27.9 + 15.50
10+(1/2)+10+(1/2) 42
------------------------- = -------
2 2
21+15=36
