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lesya [120]
3 years ago
5

What angle measure does a semicircle have? O A. 180° O B. 360° O C. 90°

Mathematics
2 answers:
user100 [1]3 years ago
7 0
A. I believe, b is a full circle and c is a right angle
photoshop1234 [79]3 years ago
5 0

Answer:180

Step-by-step explanation:

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120

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Vowels to consonants in RATIO​
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3 Vowels, 2 Constants

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the average playing time for a soccer player is calculated to be 35.4 minutes.How how much time is this to the nearest minute​
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In the third month of a study, a sugar maple tree is 82 inches tall. In the seventh month, the tree is 92 inches tall. Assuming
Eva8 [605]

The linear equation that gives the height on the x-th month is:

y = 2.5*x + 74.5

<h3>Which rule gives the height of the tree for the n-th month?</h3>

This will be modeled with a linear equation of the form:

y = a*x + b

Where a is the slope and b is the y-intercept.

Remember that for a line with the points (x₁, y₁) and (x₂, y₂), the slope is given by:

a = \frac{y_2 - y_1}{x_2 - x_1}

Here we have the two points (3, 82) and (7, 92). Where the first value is the number of months and the second value is the height.

So the slope is:

a = \frac{92 - 82}{7 - 3} = 10/4 = 2.5

Then the linear equation is:

y = 2.5*x + b

To get the value of b, we use the fact that when x = 3, we have y = 82,

82 = 2.5*3 + b

82 = 7.5 + b

82 - 7.5 = b = 74.5

Then the linear equation is:

y = 2.5*x + 74.5

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

5 0
2 years ago
If f(x, y) = esin(x + y) and D = [−π, π] × [−π, π], show the following. 1 e ≤ 1 4π2 D f(x, y) dA ≤ e The area of the region D is
Digiron [165]

I'm guessing the purpose of this exercise is to find the average value of f(x,y)=e^{\sin(x+y)} over the region D,

D=\left\{(x,y)\mid (x,y)\in[-\pi,\pi]^2\right\}

which is

\displaystyle\frac{\displaystyle\iint_Df(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_D\mathrm dx\,\mathrm dy}

The denominator is the measure (area) of D, which is easy to compute:

\displaystyle\iint_D\mathrm dx\,\mathrm dy=\int_{-\pi}^\pi\int_{-\pi}^\pi\mathrm dx\,\mathrm dy=(2\pi)^2=4\pi^2

Not to be confused with the integral in the numerator:

\displaystyle\iint_Df(x,y)\,\mathrm dx\,\mathrm dy=\int_{-\pi}^\pi\int_{-\pi}^\pi e^{\sin(x+y)}\,\mathrm dx\,\mathrm dy

but this integral is difficult to compute, hence the inequalities. We have

-1\le\sin(x+y)\le1

\implies\dfrac1e\le e^{\sin(x+y)}\le e

\implies\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}e\le\iint_De^{\sin(x+y)}\,\mathrm dx\,\mathrm dy\le\iint_De\,\mathrm dx\,\mathrm dy

\implies\displaystyle\frac{4\pi^2}e\le\iint_De^{\sin(x+y)}\,\mathrm dx\,\mathrm dy\le4\pi^2e

3 0
3 years ago
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