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Anna71 [15]
3 years ago
9

Hi! What is y = x^2 -4x +5 vertex form? Please explain how you got this answer. Thanks! :)

Mathematics
2 answers:
Anarel [89]3 years ago
8 0

{x}^{2}  - 4x + 5 = 0 \\  {x}^{2}  - 4x =  - 5 \\   \\  { (\frac{b}{2} )}^{2}  = ( \frac{ - 4}{2} ) = ( { - 2})^{2}  = 4 \\  {x}^{2}  - 4x + 4 =  - 5 + 4 \\  {(x - 2)}^{2}  =  - 1 \\  {(x - 2)}^{2}  + 1
The last line is in vertex form, and can see the vertex is located at (2,1).
alekssr [168]3 years ago
5 0
You need to do y=a(x-h)2 +k  but your vertex is ( 2,1)
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What is 3+16-2×0+1 ?
nikitadnepr [17]

<em><u>Answer: =20 *The answer should be positive sign.*</u></em>

Step-by-step explanation:

This question it's about PEMDAS. This lesson it's about order of operations. p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right.

do multiply first left to right.

2*0=0

3+16-0+1

add/subtract left to right.

3+16=19

19-0+1

19-0=19

19+1

19+1=20

<u><em>=20</em></u>

Hope this helps!

Thanks!

Have a great day!

4 0
3 years ago
Question 4: The storage in a reach of a river at a point in time is 255 m3 (meters cubed) . Determine the average rate of inflow
irakobra [83]

Answer:

0.319 m³/s

Step-by-step explanation:

Data provided:

Initial volume in the river = 255 m³

Final volume required in the storage = 325 m³

Average outflow = 0.30 m³/s

Duration for raising the level = 1 hour = 3600 seconds

Now,

The actual volume required to raise the volume to 325 m³

= Final volume - Initial volume

= 325 m³ - 255 m³

= 70 m³

also,

the amount of outflow in 1 hour = Average rate of outflow × Time

= 0.30 m³/s × 3600 s

= 1080 m³

Therefore,

the total volume required = 1080 m³ + 70 m³ = 1150 m³

Now,

the average rate of inflow required = \frac{\textup{Total volume required}}{\textup{Time}}

= \frac{\textup{1150}}{\textup{3600}}

= 0.319 m³/s

8 0
3 years ago
On
quester [9]

Answer:

\large\boxed{C.\ 2x^3-x^2-18x+9}

Step-by-step explanation:

\text{Use}\ a^2-b^2=(a-b)(a+b)\qquad(*)\\\\\underbrace{(x-3)(x+3)}_{(*)}(2x-1)=(x^2-3^2)(2x-1)=(x^2-9)(2x-1)\\\\\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(x^2)(2x)+(x^2)(-1)+(-9)(2x)+(-9)(-1)\\\\=2x^3-x^2-18x+9

3 0
3 years ago
Read 2 more answers
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Mrrafil [7]
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Step-by-step explanation:

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