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Anna71 [15]
3 years ago
9

Hi! What is y = x^2 -4x +5 vertex form? Please explain how you got this answer. Thanks! :)

Mathematics
2 answers:
Anarel [89]3 years ago
8 0

{x}^{2}  - 4x + 5 = 0 \\  {x}^{2}  - 4x =  - 5 \\   \\  { (\frac{b}{2} )}^{2}  = ( \frac{ - 4}{2} ) = ( { - 2})^{2}  = 4 \\  {x}^{2}  - 4x + 4 =  - 5 + 4 \\  {(x - 2)}^{2}  =  - 1 \\  {(x - 2)}^{2}  + 1
The last line is in vertex form, and can see the vertex is located at (2,1).
alekssr [168]3 years ago
5 0
You need to do y=a(x-h)2 +k  but your vertex is ( 2,1)
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