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Anna71 [15]
3 years ago
9

Hi! What is y = x^2 -4x +5 vertex form? Please explain how you got this answer. Thanks! :)

Mathematics
2 answers:
Anarel [89]3 years ago
8 0

{x}^{2}  - 4x + 5 = 0 \\  {x}^{2}  - 4x =  - 5 \\   \\  { (\frac{b}{2} )}^{2}  = ( \frac{ - 4}{2} ) = ( { - 2})^{2}  = 4 \\  {x}^{2}  - 4x + 4 =  - 5 + 4 \\  {(x - 2)}^{2}  =  - 1 \\  {(x - 2)}^{2}  + 1
The last line is in vertex form, and can see the vertex is located at (2,1).
alekssr [168]3 years ago
5 0
You need to do y=a(x-h)2 +k  but your vertex is ( 2,1)
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The mean score of 8 players is 14.5. If the highest individual score is removed the mean of the score of the remaining 7 players
AfilCa [17]

Answer:

The highest score is 32.

Step-by-step explanation:

We are given the following in the question:

The mean score of 8 players is 14.5.

Let x denote the highest score.

If x is removed, the mean of the score of the remaining 7 players is 12.

Formula for mean:

\bar{x} = \dfrac{\displaystyle\sum x_i}{n}

Putting values, we get:

14.5 = \dfrac{\displaystyle\sum x_i}{8}\\\\\Rightarrow \displaystyle\sum x_i = 116\\\\12 = \dfrac{\displaystyle\sum y_i}{7}\\\\\Rightarrow \displaystyle\sum y_i  = 84\\\\\displaystyle\sum y_i = \displaystyle\sum x_i -x \\\\84 = 116 - x\\\Rightarrow x = 32

Thus, the highest score is 32.

4 0
4 years ago
How can the vertex of a parabola be used in solving<br> real-world problems?
Bezzdna [24]

Answer:

The vertex is the maximum or minimum point of the quadratic function. It can be used to solve real world problems optimization problems that can be modeled with quadratic functions

Step-by-step explanation:

hope this helps^^

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7 0
3 years ago
Anna, Boris, and Clara thought of 1 number each Ana's number increased by 20 is 21 greater than boris's number decreased by 22.
sleet_krkn [62]

Answer:

Clara's number is 42 less than Anna's number

Step-by-step explanation:

We can start this problem out by setting our variables up:

A= Anna's number

B= Boris's number

C= Clara's number

so we can use them to build our equations. We can sepparate the problem into little more understandable pieces of information, let's start with the first piece of information:

- "Ana's number increased by 20"

A+20

- "boris's number decreased by 22"

B-22

- "21 greater than boris's number decreased by 22."

(B-22)+21

- "Ana's number increased by 20 is 21 greater than boris's number decreased by 22."

A+20=(B-22)+21

This is our first important equation here. Let's go with the second part of the problem:

- "Boris's number decreased by 20"

B-20

- "claras number increased by 22"

C+22

- "21 greater than claras number increased by 22"

(C+22)+21

Now the whole thing:

"Boris's number decreased by 20 is 21 greater than claras number increased by 22."

B-20=(C+22)+21

This is our second important equation.

So now we have the following system of equations:

A+20=(B-22)+21

B-20=(C+22)+21

We can now simplify the equations by combining like terms so we get:

Equation 1:

A+20=(B-22)+21

we can get rid of the parenthesis so we get:

A+20=B-22+21

We can subtract a 20 from both sides of the equation so we get:

A=B-22+21-20

We perform the subtractions so we get:

A=B-21

Equation 2:

B-20=(C+22)+21

We get rid of the parenthesis:

B-20=C+22+21

We add a 20 to both sides so we get:

B=C+22+21+20

We can now perform the additions so we get:

B=C+63

And now we can combine the equations. In this case we can substitute equation 2 into equation 1 to get:

A=C+63-21

We combine like terms to get:

A=C+42

We can subtract 42 from both sides to get:

C=A-42

which reads:

Clara's number is 42 less than Anna's number.

3 0
3 years ago
F(x+h)-f(x)/h<br> f(x) = 2x 2 + 7x
Karolina [17]
174992774 there you go chicken
7 0
3 years ago
Given P = x^0.3 y^0.7 is the chicken lay eggs production function, where P is the number of eggs lay, x is the number of workers
lora16 [44]

Answer:

Part A)

\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}

Part B)

The daily operating cost decreases by about $143 per extra worker.

Step-by-step explanation:

We are given the equation:

\displaystyle P=x^{\frac{3}{10}}y^{\frac{7}{10}}

Where <em>P</em> is the number of eggs laid, <em>x</em> is the number of workers, and <em>y</em> is the daily operating budget (assuming in US dollars $).

A)

We want to find dy/dx.

So, let’s find our equation in terms of <em>x</em>. We can raise both sides to 10/7. Hence:

\displaystyle P^\frac{10}{7}=\Big(x^\frac{3}{10}y^\frac{7}{10}\Big)^\frac{10}{7}

Simplify:

\displaystyle P^\frac{10}{7}=x^\frac{3}{7}y

Divide both sides by<em> </em>the <em>x</em> term to acquire:

\displaystyle y=P^\frac{10}{7}x^{-\frac{3}{7}}

Take the derivative of both sides with respect to <em>x: </em>

\displaystyle \frac{dy}{dx}=\frac{d}{dx}\Big[P^\frac{10}{7}x^{-\frac{3}{7}}\Big]

Apply power rule. Note that P is simply a constant. Hence:

\displaystyle \frac{dy}{dx}=P^\frac{10}{7}(-\frac{3}{7})(x^{-\frac{10}{7}})

Simplify. Hence, our derivative is:

\displaystyle \frac{dy}{dx}=-\frac{3}{7}P^\frac{10}{7}x^{-\frac{10}{7}}

Part B)

We want to evaluate the derivative when <em>x</em> is 30 and when <em>y</em> is $10,000.

First, we will need to find <em>P</em>. Our original equations tells us that:

P=x^{0.3}y^{0.7}

Hence, at <em>x</em> = 30 and at <em>y</em> = 10,000, <em>P </em>is:

P=(30)^{0.3}(10000)^{0.7}

Therefore, for our derivative, we will have:

\displaystyle \frac{dy}{dx}=-\frac{3}{7}\Big(30^{0.3}(10000^{0.7})\Big)^\frac{10}{7}\Big(30^{-\frac{10}{7}}\Big)

Use a calculator. So:

\displaystyle \frac{dy}{dx}=-\frac{1000}{7}=-142.857142...\approx-143

Our derivative is given by dy/dx. So, it represents the change in the daily operating cost over the change in the number of workers.

So, when there are 30 workers with a daily operating cost of $10,000 producing a total of about 1750 eggs, the daily operating cost decreases by about $143 per extra worker.

5 0
3 years ago
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