Answer:
The bill size can be considered usual.
Step-by-step explanation:
Mean (μ) = $108.43
Standard deviation (σ) = $36.98
Now, consider the distribution to be normal distribution :

Now, finding values of z-score from the table. We get,
P(Z > 1.75) = 0.9599
⇒ 95.99%
So, only 4.01 % of the people in the city wastes water.
Hence, the bill size can be considered usual.
Answer:
The length of BC is needed because it is the side opposite ∠A.
Step-by-step explanation:
Given the right angles triangle as shown in the attachment, we can get sin(A) without using Pythagoras theorem. Instead we will use SOH CAH TOA trigonometry identity.
According to SOH:
Sin(A) = Opposite/Hypotenuse
Sin(A) = |BC|/|AB|
Opposite side of the triangle is the side facing ∠A.
Based on the formula, we will need to get the opposite side of the triangle which is length BC for us to be able to determine sinA since the hypotenuse is given.
<h3>
Therefore the area of remaining board =13.76 square feet</h3>
Step-by-step explanation:
Given , The length of side of the square is 8 feet.
Since a circle is inscribed in the square. Then the diameter of the circle is equal to the length of side of the square .
Therefore the diameter of the circle is = 8 feet.
Radius of the circle is(r) =
feet = 4 feet
The area of the circle is= 3.14 r²
= 3.14 × 4² square feet
= 50.24 square feet
The area of the square is = side × side
= 8×6 square feet
=64 square feet
Therefore the area of remaining board = (64- 50.24)square feet
=13.76 square feet
If you're working with complex numbers, then I'm sure you're comfortable with plotting them on a complex-plane ... real part of the number along the x-axis, and imaginary part of the number along the y-axis.
When you look at it that way, your two points are simply two points on the x-y plane:
4 - i ===> (4, -1)
-2 + 3i ===> (-2, 3) .
The distance between them is
D = √ (difference in 'x')² + (difference in 'y')²
= √ (6)² + (4)²
= √ (36 + 16)
= √ (52)
= 7.211 (rounded)
Answer:
([-3], [0]), ([3], [0])
Step-by-step explanation:
The given equation of the hyperbola is presented as follows;

The vertices of an hyperbola (of the form)
are (± a, 0)
The given hyperbola can we presented in a similar form as follows;

Therefore, by comparison, the vertices of the parabola are (± 3, 0), which gives;
The vertices of the parabola are ([-3], [0]), ([3], [0]).