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3 years ago

(Vx+2)(vx-2)=0 What is x?

Mathematics

1 answer:

kumpel [21]3 years ago

5 0

Answer:

x=2

Step-by-step explanation:

if x=2 then v=1

([1×2]+2)([1×2]-2)

=(2+2)(2-2)

=(4)(0)

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PLEASE HELP

dexar [7]

Volume of a Rectangular Prism: V=lwh

l=50 cm
w= 30cm
h= 40 cm

Step 1: 50×30×40= 60,000

The volume of the tank is 60,000 cubic centimeters

The water reaches a height of 28 centimeters, or 2142.9 cubic centimeters per centimeter.

Step 2: 35× 2142.9= 75001.5 cubic centimeters

Step 3) 75001.5- 60,000= 15001.5 CUBIC CENTIMETERS ARE NEEDED TO FILL THE REST OF THE TANK TO A HEIGHT OF 35 CENTIMETERS

Hope this helps!

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3 years ago

Jaiden plays Fortnite everyday. On Wednesday, he bought 50 skins, but only used 27. What percentage of skins did Jaiden use?

DedPeter [7]

Answer:

54%

Step-by-step explanation:

27 / 50 * 100% = 54%

I hate Fortnite :/

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3 years ago

Read 2 more answers

How do you solve 3y-2=8x-32

Liono4ka [1.6K]

Y=8/3x-10 is the answer in slope intercept form

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"

qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that $\arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)$

Also, $-\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)$

This means our original expression is equal to:

$\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]$

Using the cosine addition formula, which states $\cos(a+b)=\cos a \cos b-\sin a \sin b$ , we get this itself is equal to:

$\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)$

Since $\sin^{2} \theta+\cos^{2} \theta=1$ , we know that:

$\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}$

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

$\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}$

3 0

2 years ago

HELP ASAP DUE TODAY PLZ HELP<br> Solve the equation for x.<br> 17=5+23x

LenKa [72]

Answer:

x=12/23

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

5 0

3 years ago