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3 years ago

Simplify: 3(2x-y)-(5x+4y-2) Please show steps

Mathematics

2 answers:

il63 [147K]3 years ago

7 0

Answer:

6 x ^2 − 5 x y − 4 y ^2

Step-by-step explanation:

Expand

( 2 x + y ) (3 x − 4 y )

using the FOIL Method.

Apply the distributive property.

2 x ( 3 x − 4 y ) + y ( 3 x − 4 y )

Apply the distributive property.

2 x ( 3 x )+ 2 x (− 4 y ) + y ( 3x − 4 y )

Apply the distributive property.

2 x ( 3 x ) + 2 x( − 4 y ) + y ( 3 x) + y ( −4 y )

Simplify and combine like terms.

6 x ^2 − 5 x y − 4^ 2

Gemiola [76]3 years ago

6 0

Step-by-step explanation:

so it is 3×2=6 3×y=3y so here it 6-3 =3

5+4=9-2=7

so 7-3=4

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If measurement angle L = 58 then measurement angle LKJ = _________ degrees.

Montano1993 [528]

because the sides are the same and angle L = 58, that means that angle J is also 58, so LKJ would be 180-58-58 = 64 degrees

if JKM = 48, M = 90

so J = 180 -90 -48 = 42 degrees

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3 years ago

Help! First correct answer gets brainliest

lozanna [386]

All you have to do is plug in.

x = 1 , y= 8

3x+5=y

3(1) + 5 = 8

3+5 = 8

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3 years ago

Evaluate 2LW + 2HL + 2HW for L = 3,W = 2, and H = 4. 48 46

JulijaS [17]

2(3)(2) + 2(4)(3) + 2(4)(2)

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Hope this helps!

7 0

3 years ago

Read 2 more answers

A log is floating on swiftly moving water. A stone is dropped from rest from a 50.8-m-high bridge and lands on the log as it pas

TiliK225 [7]

Answer:

Horizontal distance between the log and the bridge when the stone is released = 17.24 m

Step-by-step explanation:

Height of bridge, h = 50.8 m

Speed of log = 5.36 m/s

We need to find the horizontal distance between the log and the bridge when the stone is released, for that first we need to find time taken by the stone to reach on top of log,

We have equation of motion. s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 9.81 m/s²

Displacement, s = 50.8 m

Substituting,

s = ut + 0.5 at²

50.8 = 0.5 x 9.81 x t²

t = 3.22 seconds,

So log travels 3.22 seconds at a speed of 5.36 m/s after the release of stone,

We have equation of motion. s = ut + 0.5 at²

Initial velocity, u = 5.36 m/s

Acceleration, a = 0 m/s²

Time, t = 3.22 s

Substituting,

s = ut + 0.5 at²

s = 5.36 x 3.22 + 0.5 x 0 x 3.22²

s = 17.24 m

Horizontal distance between the log and the bridge when the stone is released = 17.24 m

3 0

3 years ago

4. Find the value of the expression below for r=4 and t=2.

Katen [24]

Answer:

(a) 9

Step-by-step explanation:

$\sf t^3 - r + 20 \div r$

substitute r = 4, t = 2

$\sf (2)^3 - 4 + 20 \div 4$

simplify

$\sf (2)^3 - 4 + 5$

cubic of 2 is 8

$\sf 8 - 4 + 5$

simplify

$\sf 9$

5 0

2 years ago

Read 2 more answers