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snow_lady [41]
3 years ago
7

Using the relation in Part B, what is the value of x if f(x) = 99?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
4 0
I hope this answer helps 

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3 years ago
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Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =
DanielleElmas [232]

Answer:

c = 5

Step-by-step explanation:

Given

f(c) = M

f(x) = x^2 - x + 1

Interval: [1,8]

M = 21

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

f(x) = x^2 - x + 1

f(1) = 1^2 - 1 + 1

f(1) = 1

f(x) = 8^2 - 8 + 1

f(x) = 57

1 \le M \le 57

1 \le 21 \le 57

M is within range.

Solving further:

We have:

f(c) = f(x) = M

f(x) = 21

Substitute 21 for f(x) in f(x) = x^2 - x + 1

21 = x^2 - x + 1

Express as quadratic function

x^2 - x + 1 - 21  = 0

x^2 - x - 20  = 0

Expand

x^2 + 4x - 5x - 20

x(x+4)-5(x+4)=0

(x - 5)(x+4) = 0

x - 5 = 0 or x + 4= 0

x = 5 or x = -4

The value of x = -4 is outside the Interval: [1,8]

So:

x = 5

f(c) = f(x) = M

f(c) = f(5) = 21

By comparison:

c = 5

4 0
3 years ago
What is the answer to 5 and 3/4 - 2 1/4
sergey [27]

Answer:

<h2>The answer you are looking for is 3 and 1/2</h2><h2>(or 7/2 or 3.5)</h2>

Step-by-step explanation:

<h2>plz mark as brainliest!!!</h2>
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