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Lynna [10]
3 years ago
9

Is y=-2x^2+3x-1 max or min

Mathematics
1 answer:
puteri [66]3 years ago
4 0
Use the formula
x
=
−
b
2
a
x
=
-
b
2
a
to find the maximum and minimum.
(
−
3
4
,
41
8
)
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Please answer this find the circumference for each of them TYSMMM
artcher [175]
For a , C= 18.85
for b , C= 21.99
for 1 , C= 75.4
for 2 , C= 87.96
6 0
2 years ago
Write an equivalent exponential equation for the following three problems.
Naily [24]

<u>Answer with step-by-step explanation:</u>

We are given three different expressions and we are to write an equivalent exponential equation for them.

We know that the standard form of a logarithmic expression is given by:

y = log_a ( x ) which is equivalent to the exponential form  x = a ^ y.

1. log _ {10} (0.1) = -1 ---> 10^{-1}=0.1

2. log _ {3} 9 = 2 ---> 3^2=9

3. log _ 5 ( \frac { 1 } { \sqrt { 5 } } ) = -\frac { 1 } { 2 } ---> 5^{-\frac{1}{2} }=\frac{1}{\sqrt{5} }

8 0
3 years ago
Two angles form a linear pair. If the measure of one angle is 47, what is the degree measure of the other angle?
cupoosta [38]

Answer:

The other angle would be equal to 133 degrees.

Step-by-step explanation:

All linear pairs are supplementary angles, which means that they are equal to 180. So we can find the second angle by using the following angle.

47 + x = 180

x = 133

8 0
3 years ago
What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1;
Mama L [17]

Answer:

The answer is: 3

Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

 double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

\\\\x=1\\y=1\\y=1/2=0.5\\x=1+0.5=1.5\\i=1

The variable x is minor to 2.5 so the loop will continue computing.

b)   the second iteration, the values of y and x are shown below::

 y=0.5\\x=1.5\\y=\frac{1.5}{2}=0.75\\ x=1.5+0.75=2.25\\i=2

The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

y=0.75\\x=2.25\\y=\frac{2.25}{2} =1.1125\\x=2.25+1.125=3.375\\i=3

The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

Therefore the number 3 is display.

6 0
3 years ago
Which solids can have vertical cross sections that are circles? Check all that apply
blsea [12.9K]

cones

cylinders

spheres

Step-by-step explanation:

The question was worded incorrectly and instead of giving the options it gave you the answers

5 0
3 years ago
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