What is the square root of -1
1 answer:
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Answer:
B
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = -
y = 3x² + 6x + 1 ← is in standard form
with a = 3 and b = 6 , then
= -
= - 1
Substitute x = - 1 into y for corresponding y- coordinate
y = 3(- 1)² + 6(- 1) + 1
= 3(1) - 6 + 1
= 3 - 5
= - 2
vertex = (- 1, - 2 )