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mars1129 [50]
3 years ago
12

Solve for please X/2+6=-2

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
8 0
X=-16
X/2+6=-2
Subtract 6 from both sides
X/2=-8
Multiply by 2
X=-16
mina [271]3 years ago
3 0

Answer:

x = -16

Step-by-step explanation:

You might be interested in
15 times the square of a nonzero number is equal to 20 times the number
melisa1 [442]

Answer:

Let the number be x

The expression above is written as

15x² = 20x

Divide both sides by x

We get

15x²/x = 20x/x

15x = 20

Divide both sides by 15

x = 20/15

x = 4/3

Hope this helps

4 0
3 years ago
HELP DUE in 20 MIN<br> m∠16 =
Ierofanga [76]

9514 1404 393

Answer:

  ∠16 = 47°

Step-by-step explanation:

Vertical and corresponding angles are congruent. The remainder are supplementary to those.

∠1≅∠4≅∠5≅∠7≅∠10≅∠12≅∠13≅∠15 = 133°

∠2≅∠3≅∠6≅∠8≅∠9≅∠11≅∠14≅∠16 = 47°

8 0
3 years ago
the midpoint of [KL] is (-8, 1). one endpoint is K(-6, 5). find the coordinates of the other endpoint L
ExtremeBDS [4]

the correct question is

The midpoint of kl is m(–8, 1). one endpoint is k(–6, 5). find the coordinates of the other endpoint l.


we know that

the formula of midpoint is

Xm=(x1+x2)/2----> 2*Xm=x1+x2------> x2=2*Xm-x1

Ym=(y1+y2)/2----> 2*Ym=y1+y2------> y2=2*Ym-y1


let

(x1,y1)-------> (–6, 5).

(Xm,Ym)-----> (-8,1)


find (x2,y2)

x2=2*Xm-x1-----> 2*(-8)-(-6)----> -10

 y2=2*Ym-y1----> 2*(1)-5-----> -3


the point l is (-10,-3)




3 0
3 years ago
If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
s344n2d4d5 [400]
From the first equation
6x - y = 1
6x - y - 1 = 0
6x - 1 = y

Substituting we get
4x - 3(6x - 1) = -11
5 0
3 years ago
Help Anyone please? &gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;
denis-greek [22]

Answer:

the answer is c

Step-by-step explanation:

y = 5x

as it says x + y = 10

so one number which is represented as x is times 5 as the other which brimg to our answer y =5x

8 0
2 years ago
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