Answer:
The cost of each:
1 cheese slice = c = $3.75
1 pepperoni slice = p = $2.5
Step-by-step explanation:
Let the cost:
1 cheese slice = c
1 pepperoni slice = p
Two friends are going to the mall to buy pizza.
One of the friends buys 1cheese slice and 2 pepperoni slices for $8.75.
c + 2p = $8.75.....Equation 1
c = $8.75 - 2p
Her friend purchases 2 chese slices and 3 pepperoni slices for $15.00.
2c + 3p = $15.00.....Equation 2
We substitute 8.75 - 2p for c in Equation 2
2(8.75 - 2p) + 3p = $15.00
17.5 - 4p + 3p = 15
Collect like terms
- 4p + 3p = 15 - 17.5
-p = -2.5
p = $2.5
c = $8.75 - 2p
c = $8.75 - 2(2.5)
c = $8.75 - 5.0
c = $3.75
The cost of each:
1 cheese slice = c = $3.75
1 pepperoni slice = p = $2.5
Answer:
11 x 2^3 =11 x 2 x 2 x 2 = 88
Step-by-step explanation:
88
<u>11</u> 8
<u>2</u> 4
<u>2</u> <u>2</u>
<u />
Use a factor tree it helps a lot :0).
<span>Equation at the end of step 1 :</span><span> (((x3)•y)-(((3x2•y6)•x)•y))-6y = 0
</span><span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
<span> -3x3y7 + x3y - 6y</span> = <span> -y • (3x3y6 - x3 + 6)</span>
Trying to factor a multi variable polynomial :
<span> 3.2 </span> Factoring <span> 3x3y6 - x3 + 6</span>
Try to factor this multi-variable trinomial using trial and error<span>
</span>Factorization fails
<span>Equation at the end of step 3 :</span><span> -y • (3x3y6 - x3 + 6) = 0
</span><span>Step 4 :</span>Theory - Roots of a product :
<span> 4.1 </span> A product of several terms equals zero.<span>
</span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span>
</span>We shall now solve each term = 0 separately<span>
</span>In other words, we are going to solve as many equations as there are terms in the product<span>
</span>Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : -y = 0<span>
</span>Multiply both sides of the equation by (-1) : y = 0
The answer would be “Greater than.”
