3x^2+ 2x -18x -12
= (3x^2+ 2x) -(18x+ 12)
= x(3x+ 2) -6(3x+ 2)
= (3x+2)(x-6)
Final answer: (3x+2)(x-6)
Answer:
just subtract and u should get 10,963
Answer:
ok hold on
Step-by-step explanation:
Answer:
Released oxygen mass: 15.92 kg
Step-by-step explanation:
ideal gas law : P*V=nRT
P:pressure
V:volume
T:temperature
n:number of moles of gas
n [mol] = m [g] /M [u]
m : masa
M: masa molar = 15,999 u (oxygen)
R: ideal gas constant = 8.314472 cm^3 *MPa/K*mol =
grados K = °C + 273.15
P1*V*M/R*T = m1
P2*V*M/R*T = m2
masa released : m1-m2 = (P1-P2) * V*M/R*T
m2-m1 = 200 * 10^-3 MPa * 12 * 10^6 cm^3 * 15.999 u / 8.314472 (cm^3 * MPa/K *mol) * 290. 15 K
m2-m1= 38 397.6 * 10^3 u*mol / 2412.44 = 15916.5 g = 15.9165 kg