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chubhunter [2.5K]
2 years ago
8

A motorboat travels 204 kilometers in 6 hours going upstream. It travels 372 kilometers going downstream in the same amount of t

ime. What is the rate of the boat in still water and what is the rate of the current?
Mathematics
1 answer:
Arturiano [62]2 years ago
5 0

9514 1404 393

Answer:

  • boat: 48 km/h
  • current: 14 km/h

Step-by-step explanation:

The upstream speed is ...

  u = (204 km)/(6 h) = 34 km/h

The downstream speed is ...

  d = (372 km)/(6 h) = 62 km/h

The speed of the boat in still water is the average of these values:

  b = (34 kph +62 kph)/2 = 48 kph

The speed of the water is the difference between the boat's speed and the speed made good:

  w = 48 -34 = 14 . . . km/h

The rate of the boat in still water is 48 km/h. The rate of the current is 14 km/h.

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Answer:

Height = 8 units

Step-by-step explanation:

Area of a triangle = 36\frac{4}{5} square units

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Height of the triangle = 9\frac{1}{5} units

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Formula to calculate the area of a triangle is,

Area = \frac{1}{2}(\text{Base})(\text{Height})

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\frac{184}{5}= (\frac{46}{10})\times (\text{Height})

Height = \frac{184}{5}\times \frac{10}{46}

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If you take the -x substitution from the last step and then multiply it by -1, you'd have:

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