Translate the sentence into an inequality. The product of C and 9 is at most -28
1 answer:
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Answer:
Undefined
Step-by-step explanation:
1. In order to even begin to answer this question, we'll need to find the definition of a few terms:
Coefficient: A constant quantity placed before a variable in an equation.
- ex: the <em>3 </em>in the expression 3x^3 is the coefficient.
The expansion of an equation is the unfactored version of an equation.
- ex: x^2 +2x + 1 is the expansion of (x + 1)^2
2. Based on these definitions, the question is asking:
"What number is in front of of x^3 in the expanded version of (6x + 5y)^4?"
It still sounds super confusing, but at least its comprehensible.
3. Now that we know what we're being asked for, we can begin to solve... but how? Expanding (6x + 5y)^4 seems like it would take forever right?
This is when it gets complicated. You'll to have a couple concepts in your mind:
- The equation
. This is called the Combination Formula
- Pascal's Triangle. I recommend finding an image of it.
<em>If what I'm doing right now seems confusing, look up how to, "Find the Coefficient of an Expansion." I checked and there are videos on this.</em>
4. Here is the order of how we solve this problem from this point forward:
- Define our variables
- Translate our variables into the format that our question is asking for.
- Plug the translated variable into the Combination Formula.
- Solve
5. We are given two different variables to expand. (6x) and (5y). The question is asking for the coefficient in front of x^3, so our format is (6x)^3(5y)^0. The 5y should still be shown although its exponent is 0.
<em>I'm going to have to again stress looking for videos on what exactly I'm doing. I'm sorry that I can't properly teach Combinations. From this point on you may have trouble understanding what's going on.</em>
Math:
- (6x)^3(5y)^0
(6x)^3(5y)^0
Change into the format of the Combination Formula
Now plug this back into our equation
- = (4!/(4! - 4!)) (6x)^3(5y)^0
- = (4!/0) (6x)^3
- undefined
There is no term containing x^3 based on the fact that is undefined.
I hope that you can figure out Combinations. I remember learning about them, but it is a very conceptual concept. Once you do figure out how they work though, they become very easy to use. Good luck on your math.