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liraira [26]
3 years ago
5

What is the molal concentration of a solution made by dissolving 34.2 g of sucrose, c12h22o11 (molar mass 342.34 g/mol), in 125

g of water?
Chemistry
2 answers:
Anna007 [38]3 years ago
7 0
Molality is the number of moles of solute in 1 kg of solvent
number of moles of sucrose - mass of sucrose / molar mass
number of moles of sucrose - 34.2 g / 342.34 g/mol = 0.0999 mol
number of moles in 125 g of water - 0.0999 mol 
therefore number of moles in 1000 g - 0.0999 / 125 x 1000 = 0.799 mol/kg
molality of sucrose solution - 0.799 mol/kg
Alborosie3 years ago
6 0

Answer:

0.799 mol

Explanation:

Molality is the number of moles of solute in 1 kg of solvent

number of moles of sucrose - mass of sucrose / molar mass

therefore number of moles in 1000 g - 0.0999 / 125 x 1000 = 0.799 mol

Molality of sucrose solution - 0.799 mol

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For a particular reaction, δh = 120.5 kj and δs = 758.2 j/k. calculate δg for this reaction at 298 k.
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Data Given:
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Using Formula,
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Putting Values,
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                                    ΔG  =  -1.059 × 10⁵ J

                                    ΔG  =  -105.94 kJ
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3 years ago
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Answer:

B. Extreme heat and pressure.....

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